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netineya [11]
3 years ago
12

ABC stock sold for $64.50 four days later the same stock sold for $47.10 what is the average change per day?

Mathematics
1 answer:
frozen [14]3 years ago
4 0
So you subtract 64.50 - 47.10 and it equals 17.4 and then you divide that by 4 and your answer is 4.35
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Mark transferred songs from his computer onto his portable music player. He transferred 2 6/7 songs in 1 2/3 minutes. How many s
dimulka [17.4K]
This is basically unit rate. So we make them into mixed numbers. 2 6/7 = 12/7. 1 2/3 = 5/3. Then we have to divide them. 12/7 divided by 5/3= 12/7 times 3/5 because u have to flip the second one. Keep, Change, and Flip is my motto. Then u will get 36/35. Simplified it will be 1 1/35. I also never said it was right, so if u get it wrong, because of me I'm sorry I tried.
4 0
2 years ago
Read 2 more answers
HELP ME !!!!! <br> Help me please !!!!
lora16 [44]

Answer: 141.3cm^3

Step-by-step explanation:

Pi((3)^2)(-5)

Pi(9)(5)

Pi(45)

3.14×45

141.3

8 0
2 years ago
16+ n/4 =22 <br><br> Help me solve please and thank you :))
Luden [163]

Answer:

n = 24

Step-by-step explanation:

16+ n/4 =22

Subtract 16 from each side

16-16+ n/4 =22-16

n/4 = 6

Multiply each side by 4

n/4*4 = 6*4

n = 24

4 0
3 years ago
Thomas creates the table shown to represent the function ƒ(x) = x2 + 3x - 10. determine the zeros of the equation.
Eddi Din [679]
Answer: A

Explanation: The zeroes of f(x) are the value/s of x such that f(x) = 0. So, we need to find the values of x in the equation f(x) = 0.

Note that

f(x) = 0
⇔ x² + 3x - 10 = 0

By factoring into binomials, x² + 3x - 10 = (x + 5)(x - 2). Thus, 

x² + 3x - 10 = 0
⇔ (x + 5)(x - 2) = 0
⇔ x + 5 = 0 or x - 2 = 0
⇔ x = -5 or x = 2

Hence, the zeroes of x are  -5 and 2. 
4 0
3 years ago
Nadia plans to paint her jewelry box. The box is shaped like a rectangular prism with the dimensions
Pachacha [2.7K]

Answer:

132\ in^{2} is closest to the total surface area of the box

Step-by-step explanation:

we know that

The surface area of the box is equal to

SA=2B+PH

where

B is the area of the base

P is the perimeter of the base

H is the height of the box

we have

L=7\frac{3}{4}\ in=\frac{7*4+3}{4}=\frac{31}{4}\ in

W=3\frac{1}{4}\ in=\frac{3*4+1}{4}=\frac{13}{4}\ in

H=3\frac{7}{8}\ in=\frac{3*8+7}{8}=\frac{31}{8}\ in

<em>Find the area of the base B</em>

B=LW

B=(\frac{31}{4})(\frac{13}{4})=\frac{403}{16}\ in^{2}

<em>Find the perimeter of the base P</em>

P=2(L+W)

P=2(\frac{31}{4}+\frac{13}{4}))

P=2(\frac{44}{4})=22\ in

<em>Find the surface area</em>

SA=2(\frac{403}{16})+22(\frac{31}{8})

SA=(\frac{403}{8})+(\frac{682}{8})

SA=\frac{1,085}{8}=135.625\ in^{2}

6 0
3 years ago
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