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marishachu [46]
3 years ago
13

Marcus hikes at a rate of 2 miles per hour if he hikes for 6 1/3 hours how many will he hike

Mathematics
2 answers:
maria [59]3 years ago
5 0

Answer:

Marcus will walk 38/3 miles.

Step-by-step explanation:

Given data

  • Rate of hiking (r): 2 miles per hour = 2 mi/h
  • Time elapsed (t): 19/3 hours

6 1/3 = 6 + 1/3 = 18/3 + 1/3 = 19/3

We can find the distance (d) that he walks using the following expression.

r = d/t

d = r × t = 2 mi/h × 19/3 h = 38/3 mi = (36 + 2)/3 mi = 12 2/3 mi

Marcus will walk 38/3 miles.

Firdavs [7]3 years ago
3 0
2 = 1 hour               
x = 6 1/3   

2 * 6 1/3 = 12 2/3
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| Solve the equation. Check your solution.<br> d- 1/12 = 5/12
charle [14.2K]
I think it's 1/2, which is 6/12.

5/12 plus 1/12 equals 6/12. 6 is half of 12, so you one half. I hoped this helped.
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g If a hypothesis test with a significance level of α rejects H0: μ1=μ2 in favor of Ha: μ1≠μ2, then thecorresponding (1- α)% con
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Answer:

The statement, (1- <em>α</em>)% confidence interval for (μ₁ - μ₂) does not contain zero is TRUE.

Step-by-step explanation:

The hypothesis for a test is defined as follows:

<em>H</em>₀: μ₁ = μ₂ vs. <em>H</em>ₐ: μ₁ ≠ μ₂

It is provided that the test was rejected st the significance level <em>α</em>%.

If a decision is to made using the confidence interval the conditions are:

If the null hypothesis value is not included in the (1 - <em>α</em>)% confidence interval then the null hypothesis will be rejected and vice versa.

In this case the null hypothesis value is:

<em>H</em>₀: μ₁ - μ₂ = 0.

If the value 0 is not included in the (1 - <em>α</em>)% confidence interval for the difference between two means, then the null hypothesis will be rejected.

Thus the statement, (1- <em>α</em>)% confidence interval for (μ1- μ2) does not contain zero is TRUE.

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3 years ago
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vagabundo [1.1K]
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hope this helps:)
3 0
3 years ago
Read 2 more answers
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strojnjashka [21]

Answer:

2500 pence (C = 2500)

Step-by-step explanation:

C = 10t + 20m

From the given information, t is the number of texts so essentially you will plug in the number of texts provided (150) in the place of the variable t.

C = 10(150) + 20m

Apply the same thing to minutes, plug in the number of minutes (50) in the place of the variable m.

C = 10(150) + 20(50)

Now multiply the substitutes with the co-efficient.

C = 1500 + 1000 (10*150=1500 & 20*50=1000)

Add the addends

C = 2500

7 0
2 years ago
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