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Bess [88]
4 years ago
12

The figure shows the location of 3 points around a lake. The length of the lake, BC, is also shown. (Figure is not drawn to scal

e.) A picture of a right triangle ABC with right angle at B is shown. The length of the side AC is labeled as 9 miles. The length BC of the triangle is labeled as 6 miles. This length BC is also the length of an irregular gray shaded shape. Which of the following options is closest to the distance (in miles) between points A and B? 6.71 miles 7.35 miles 8.66 miles 10.82 miles.
Mathematics
1 answer:
icang [17]4 years ago
3 0
6.71 miles

use the Pythagorean theorem 

6^2 + x^2 = 9^2

36 + x^2 = 81
81-36= 45 

square root of 45 is approximately 6.71 miles
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Solve.
Anna [14]

Answer:

The first angle is 68.

Step-by-step explanation:

x_{1}+x_{2}+x_{3}=180\\x_{1} = 4*x_{2}\\x_{3}=x_{2}+ 78\\4*x_{2} + x_{2} + x_{2}+ 78 = 180\\6*x_{2}=102\\x_{2} = 17\\

So x_{1}=68 and x_{3}=95

8 0
3 years ago
Which is greater-1.03 or -1.25
Fed [463]
-1.25 is greater because if u can it like this 1.25 1.03 it will still be greater
6 0
4 years ago
With the spot rate E_VND/USD = 21,000, the Forward Rate: F_VND/USD = 21,250; the Expected Rate after 3 months: Ee_VND/USD = 22,0
mihalych1998 [28]

Answer:

Step-by-step explanation:

The importer needs to make the payment in the VND each time so the importer may enter into hedge to protect himself from the appreciation of the VND against the dollar, now if the importer enters into the forward contract of the hedge and he come across the reverse situation that means the VND is depriciating that means if the hedger would not have entered into a forward contract then they would have benefited more.

Lets convert above above rate in per VND rate to understand better.

E_USD/VND = 1/21000 = 0.000048

F_USD/VND = 0.000047

Ee_USD/VND = 0.000045

so as we can see above if we had enter into a hedge contract we have to pay the 0.000047 per VND and if we would not have enter into the contract we would have to pay the 0.000045 per VND hence cost of Hedging is 0.00002 USD per VND.

4 0
3 years ago
Please SOMEONE help me on this asap!!!
VARVARA [1.3K]
As x increases, the value of p(x) approaches a number that is y-int value of q(x)
y- int of the function p is -2 (one more) the y-int of the function q

What choices there are, then I can answer more exactly

8 0
4 years ago
Read 2 more answers
The company also discovered that it costs $25 to produce 2 camera cases, $59 to produce 4 camera cases and $305 to produce 10 ca
sasho [114]

Answer:

Cost of 5 camera cases is $85.

Step-by-step explanation:

First we need to determine what type of function we're dealing with, is it linear, quadratic or exponential?  We can determine this by calculating the first difference.

We can translate the number of cameras to correspond to the x axis and cost to the y axis.  By doing this we can come up with the ordered pairs of (2,25), (4,59),(10,305).  Let's get the first two ordered pairs and calculate the first difference:

\frac{59-25}{4-2}=17

And now the second and third value:

\frac{305-59}{10-4}=41

Notice how these values do not match, this means that this function is not increasing at a constant rate meaning that this function is not linear.  Now let's calculate the second difference:

\frac{41-17}{10-2}=3

This means our function is quadratic with a=3.  Remember that generally speaking a quadratic function is such that:

y=ax^2+bx+c

Where a,b,c are coefficients and in this case a=3.  Now, let's solve for b and c values by using the coordinates given.  Let's use the coordinates (2,25) where x=2 and y=25 and so:

f(x)=ax^2+bx+c\\\\25=3(2)^2+b(2)+c\\25=3(4)+2b+c\\25=12+2b+c\\13=2b+c\\\\b=\frac{13-c}{2}

Now let's solve for "c" by using different coordinates (4,59) where x=4 and y=59 and also use the "b" value that we calculated above and so:

f(x)=ax^2+bx+c\\\\59=3(4)^2+(\frac{13-c}{2})(4)+c\\59=48+\frac{52-4c}{2}+c\\11=\frac{52-4c+2c}{2}\\11=26-2c+c\\-15=-c\\\\c=15

Now that we know the value of "c" we can use the equation for b to solve for b and so:

b=\frac{13-c}{2}=\frac{13-15}{2}\\\\b=-1

So this means in the quadratic equation a=3, b=-1 and c=15 therefore by using the general equation of a quadratic function we obtain or final equation:

f(x)=ax^2+bx+c\\\\f(x)=3x^2-x+15

Since we want to find the total cost of producing 5 camera cases x=5 and so:

f(x)=3x^2-x+15\\\\f(5)=3(5)^2-(5)+15\\f(5)=75-5+15\\\\f(5)=85


And so the cost of 5 camera cases is $85.


3 0
3 years ago
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