The standard form of a quadratic equation is ,
ax² + bx + c = 0.
And the formula to find the discriminant is b² - 4ac.
Here the first step is to change the given equation into standard form. So, add 1 to each sides of the equation. Therefore,
2x² – 9x + 2+1 = –1 + 1
2x² – 9x + 3 = 0
Next step is to compare the given equation with this equation to get the value of a, b and c.
After comparing the equations we will get a = 2, b = -9 and c = 3.
So, discriminant = b²- 4ac
=( -9)²-4 (2)(3)
= 81 - 24
= 57
So, discriminant of the given equation is 57.
57 is greater than 0 and square root of 57 will result real number.
So, the correct choice is C: The discriminant is greater than 0, so there are two real roots.
Answer:
205
Step-by-step explanation:
Answer:
(1, 6 )
Step-by-step explanation:
5x + 2y = 17 → (1)
4x + y = 10 → (2)
Multiplying (2) by - 2 and adding to (1) will eliminate the y- term
- 8x - 2y = - 20 → (3)
Add (1) and (3) term by term to eliminate y
- 3x + 0 = - 3
- 3x = - 3 ( divide both sides by - 3 )
x = 1
Substitute x = 1 into either of the 2 equations and solve for x
Substituting into (1)
5(1) + 2y = 17
5 + 2y = 17 ( subtract 5 from both sides )
2y = 12 ( divide both sides by 2 )
y = 6
solution is (1, 6 )
The answer for your questions is -5
Where are the sets? I don't see any...
