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3 years ago

15(y - 4) - 2 (y - 2 )= - 5 (y+ 6) pls solve fast step by step

Mathematics

2 answers:

Arturiano [62]3 years ago

8 0

Answer:

13/9

Step-by-step explanation:

Step 1: simplify

15y-60-2y+4= - 5y-30

Step 2: group like terms together

18y= 26

Step 3: simplify

y=13/9

dalvyx [7]3 years ago

7 0

Answer:

y= 13/9

Step-by-step explanation:

we apply distributive property:

15(y - 4) - 2 (y - 2 )= - 5 (y+ 6)

15*y-15*4 -2*y +2*2 = -5*y -5*6

we have:

15y - 60 -2y +4 = -5y -30

13y - 56 = -5y -30

13y+5y =56 - 30

y= 26/18

so y = 13/9

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Please helpppp me ! If the sum of the roots of the equation mx^2 - (6m+1)x+m^3+m^2+4=0 is equal to 7 , what is the product of it

zepelin [54]

Answer:

The product of its roots is 6.

Step-by-step explanation:

Let $m\cdot x^{2}-(6\cdot m +1)\cdot x+(m^{3}+m^{2}+4) = 0$ , all roots are calculated by Quadratic Formula:

$r_{1} = \frac{6\cdot m +1 + \sqrt{(6\cdot m + 1)^{2}-4\cdot m\cdot (m^{3}+m^{2}+4)}}{2\cdot m}$ (1)

$r_{2} = \frac{6\cdot m +1 - \sqrt{(6\cdot m + 1)^{2}-4\cdot m\cdot (m^{3}+m^{2}+4)}}{2\cdot m}$ (2)

According to statement, we know that:

$r_{1}+r_{2} = 7$ (3)

By applying (1) and (2) in (3), we have the following expression:

$\frac{6\cdot m +1}{m} = 7$

$6\cdot m + 1 = 7\cdot m$

$m = 1$

If we know that $m = 1$ , then the roots of the polynomial are, respectively:

$x^{2}-7\cdot x +6 = 0$

$r_{1} = 6$

$r_{2} = 1$

And the product of the roots is:

$r_{1}\cdot r_{2} = 6$

The product of its roots is 6.

7 0

2 years ago

Difference is 0, product is 25

vladimir2022 [97]

So difference means subtract
x-y=0
product means multipy
x times y=25

we see from x-y=0 that x=y
so
x times y=25
x times x=25
what number times itself=25?
answer is 5
x=5
x=y
y=5

then numbers ae 5 and 5

7 0

3 years ago

How do you graph linear equation x+y=4

Sliva [168]

Answer:

See attached picture.

Step-by-step explanation:

To graph the linear equation, convert x+y=4 into y= -x+4. This means that y= mx+b is y=-x+4. So m = -1 and b =4.

Start with b by finding 4 on the y-axis. Plot a point. Then from this point move down 1 unit and 1 unit to the right to (1,3). Plot this point. Connect the points.