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mart [117]
3 years ago
7

Ming has 15 quarters, 30 dimes, and 48 nickels. He wants to group his money so that each group had the same number of each coin.

What is the greatest number of groups he can make? How many of each coin will be in each group? How much money will each group be worth?
Mathematics
1 answer:
Colt1911 [192]3 years ago
3 0
Find the greatest common factor. In this case it is 3. Divide each group by 3.
15÷3=5 quarters
30÷3=10 dimes
48÷3=16 nickels
Next count them by the coin's value:
5 × 0.25 = $1.25
10 × 0.10 = $1
16 × 0.05 = $0.80
Add them up:
= $3.05 in each group and there are three groups.

So, the greatest number of groups that he can make is 3; there will be 5 quarters, 10 dimes, and 16 nickels in each group, which is worth $3.05 in each group.
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jeka57 [31]
Given:
a + bi = 13 + 9i

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Answer:
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Step-by-step explanation:

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cross-multiply:

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2 years ago
The rate of change from 23 to 30 is
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7

Step-by-step explanation:

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2 years ago
Help asap! will award brainly and pls explain!
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This is a right angle triangle.

So, by Pythagoras theorem,

√(32^2+20^2) = x

or √(1024+400) = x

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3 0
2 years ago
p borrowed Rs. 16000 from a person at 12 % per Annum simple interest and lent the whole amount to Q at the same rate of annually
hichkok12 [17]

Answer:

P earned $ 718.85.

Step-by-step explanation:

Given that P borrowed $ 16000 from a person at 12% per annum simple interest and lent the whole amount to Q at the same rate of annually compound interest, to determine how much did he gain after 3 years the following calculation must be performed:

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