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EastWind [94]
3 years ago
12

Find the midpoint of (-3,-5), (4,5) * (3,2) O (-6,4) (0.5,0) O (-1,-3)

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
3 0

Answer:

(0.5, 0) will be the midpoint by applying formula which is

add both "x" quadrant and divide by it by two and then add both "you" quadrant and then divide it also by 2 you will get answer

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weeeeeb [17]

Answer:15

Step-by-step explanation: 7 and a half times 2 is 15

6 0
3 years ago
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Write the equation of the line that passes through the given point and is parallel to the given line.
Mekhanik [1.2K]

Answer:

y= -3/5x + 2

Step-by-step explanation:

5 0
2 years ago
The diagram below shows an Isosceles triangle. Label the base angles and the vertex
Dmitry [639]

The base angles of an isosceles triangle are equal

The base angles are 15 degrees, while the vertex angle is 150 degrees

The base angles are given as:

Base = (6a- 3) and (a + 12)

So, we have:

\mathbf{6a -3 =a + 12}

Collect like terms

\mathbf{6a -a =3 + 12}

\mathbf{5a = 15}

Divide both sides by 5

\mathbf{a = 3}

Substitute 3 for a in Base = (6a- 3),

\mathbf{Base = 6 \times 3 - 3}

\mathbf{Base = 18 - 3}\\

\mathbf{Base = 15}

So, the base angle is 15 degrees.

The vertex angle is calculated using:

\mathbf{Vertex=180 -2 \times Base}

So, we have:

\mathbf{Vertex=180 -2 \times 15}

\mathbf{Vertex=150 }

Hence, the vertex angle is 150 degrees

Read more about isosceles triangles at:

brainly.com/question/25739654

6 0
2 years ago
Circle O, with center (x, y) passes through the points A(0, 0), B(-3, 0), and C(1, 2). Find the coordinates of the center of the
KonstantinChe [14]

Answer:

The center of the circle is

(-\frac{3}{2},2)

Step-by-step explanation:

Let the equation of the circle be

x^2+y^2+2ax+2by+c=0, where (-a,-b) is the center of this circle.

The points lying the circle must satisfy the equation of this circle.

A(0,0)

We substitute this point to get;

0^2+0^2+2a(0)+2b(0)+c=0

\implies c=0

B(-3,0)

(-3)^2+0^2+2a(-3)+2b(0)+c=0

\implies 9+0-6a+0+c=0

\implies -6a+c=-9

But c=0

\implies -6a=-9

\implies a=\frac{3}{2}

C(1,2)

1^2+2^2+2a(1)+2b(2)+c=0

1+4+2a+4b+c=0

2a+4b+c=-5

Put the value of 'a' and 'c' to find 'b'

2(\frac{3}{2})+4b+0=-5

3+4b+0=-5

4b=-5-3

4b=-8

b=-2

Hence the center of the circle is

(-\frac{3}{2},2)

8 0
3 years ago
What is the volume of the cylinder? Do not round your answer. (Use 3.14 for π .)
vitfil [10]

Answer:

When I used a cylinder calculator I got 6785.84 yd^3

Step-by-step explanation:

7 0
3 years ago
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