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vladimir1956 [14]
3 years ago
5

HELP! WILL MAKE BRAINLEST What is the equation of this line? y=2x−3 y=−1/2x−3 y=−2x−3 y=1/2x−3

Mathematics
2 answers:
Luden [163]3 years ago
5 0

The answer is y = 2x - 3. Because you'll first start a point -3. Now 2x would change and add an invisible on making it 2/1. Then from point -3. You'll rise up 2 units and run 1 unit to the right. Showing exactly in the graph.

Dennis_Churaev [7]3 years ago
3 0

Answer:

Y = 2x-3

Step-by-step explanation:

You start at the point -3. THen as you find the y value you will go up by two units and then go 2 units to the right. THis will give u ur answer if y=2x-3. Hope this helps!

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Towns X, Y, and Z are on the same straight road. Town Y is between Town X and Town Z. Town X is 57 miles from Town Z, and Town Y
Ber [7]
29 miles 
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4 years ago
A researcher conducted a paired sample t-test to determine if advertisements were viewed more in the morning (before noon) or in
Natalija [7]

Answer:

b. No, there was no difference between Morning (M= 32), and Evening (M=40.625), (t [7] = 1.15, p > .05).

Step-by-step explanation:

The critical value for one tailed test is t ∝(7) > 1.895

A one tailed test is performed to test the claim that advertisements were viewed more in the morning (before noon) or in the evening (after 5pm)

The null and alternative hypotheses are

H0: μm = μe   vs     Ha μm > μe

where μm is the mean of the morning and μe is the mean of evening.

The calculated value of t = -1.152587077  which is less than the critical region hence the null hypothesis cannot be rejected .

P(T<=t) one-tail 0.143458126 > 0.05

If two tailed test is performed the critical region is t Critical two-tail 2.364624252

and the calculated t value is  -1.152587077  which again does not lie in the critical region .

Hence μm =  μe or    μm ≤ μe

P(T<=t) two-tail 0.286916252  > 0.025

Therefore

b. No, there was no difference between Morning (M= 32), and Evening (M=40.625), (t [7] = 1.15, p > .05).

Option b gives the best answer.

6 0
3 years ago
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neonofarm [45]
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Read 2 more answers
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Dmitry_Shevchenko [17]

Answer:

0.78

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given that 80% of an airline's flights depart on-time and 20% do not.

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Now A and A' are mutually exclusive and exhaustive

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Using total probability calculation we have

the chance of someone taking a flight that will arrive on-time

= P(B)

=P(A)+P(A'B)\\= 0.80(0.95) +0.20(0.10)\\= 0.76+0.02\\=0.78

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