Treat x^4 as the square of p: x^4 = p^2.
Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.
This factors nicely, to (p-9)(p+4) = 0. Then p = 9 and p = -4.
Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.
Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
Answer:
-(-9) is 9
Step-by-step explanation:
-(-9)
(when there are two negatives multiplyed with eachother, the product will be postive)
+ 9
+ 9 = 9
1. Check picture 1. Let the one side of the triangle be a, drop one perpendicular, CD. Then triangle ADB is a right triangle, with hypothenuse a and one side equal to 1/2a. By the Pythegorean theorem, as shown in the picture, the height is

2. if a a=25 ft, then the height is

(ft)
3. consider picture 2. Let the length of the roof be l feet.
one side of the prism (the roof) is a rectangle with dimensions a and l, so the area of one side is a*l
the lateral Area of the roof is 3a*l
the area of the equilateral surfaces is

so the total area of the roof is

4. The total area was the 2 triangular surfaces + the 3 equal lateral rectangular surfaces. Now instead of 3 lateral triangular surfaces, we have 2.
So the total area found previously will be decreased by al
5. so the area now is

6. now a=25 and l=2a=50
Area=

=3041.3 (ft squared)
Answer:
x<1
Step-by-step explanation:
Answer:
121..??
Step-by-step explanation: