Hey its p(A) = 0.1 and q(a) = 0.9
The percentage in the population of heterozygous
individuals:
2pq = 2 x 0.1 x 0.9 = 0.18 = 18%
The compromise of 1877 for apex :) hope this helps
Answer:
Explanation:
Given -
Total Population - 
Individuals with homozygous HbA/hbA genotype - 
Individuals with homozygous hbs/hbs genotype -
Individuals with heterozygous hba/hbs genotype - 
Let us assume the given population is in Hardy Weinberg' equilibrium
The frequency of individuals in the given population with homozygous HbA/hba genotype is equal to number of individuals with homozygous HbA/hba genotype divided by total population.
The frequency of hba allele is equal to
Molecules that are present in the membranes of gram-negative bacteria and are the best-known pamps are called Bacterial lipopolysaccharides (LPSs).
Bacterial lipopolysaccharides (LPS) are the primary outer surface membrane elements present in almost all Gram-negative bacteria and it act as extremely strong stimulators of the innate or natural immunity in the diverse eukaryotic species ranging from insects to humans.
Eukaryotes are the organisms whose cells contain a nucleus and other membrane-bound organelles. eukaryote, any cell or organism that possesses a clearly defined nucleus. The first eukaryotic cells was evolved about 2 billion years ago. In this Cells with nuclei surrounded by a nuclear envelope with nuclear pores.
Learn more about lipopolysaccharides (LPSs) here
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