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3 years ago

6

What's (2×2)÷2=???????????????????????

2 answers:

Amiraneli [1.4K]3 years ago

8 0

Answer:

2

Step-by-step explanation:

2×2=4

4÷2=2

Tema [17]3 years ago

4 0

Answer:

2

Step-by-step explanation:

2 x 2 = 4

4 / 2 = 2

the answer is 2

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What is the volume of the sphere shown below with a radius of 3?

kaheart [24]

Answer:

volume of the sphere

=4/3π × r³

=4/3π × 3 × 3 × 3

=4/3π × 27

=36π ( <em>c</em><em> </em><em>)</em>

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3 years ago

If the tape diagram represents a 10-pound bag of almonds, but a baker only uses 3/4 of a bag (the shaded region), how many pound

ale4655 [162]

Answer:

7.5 lbs.

Step-by-step explanation:

A fraction is a division problem so to turn it into a decimal you divide 3 by 4. 0.75. 0.75 multiplied by 10 lbs. is 7.5 lbs.

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2 years ago

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3×52 A. 5/6 B. 15/2 C.8/2 D.15/6

ohaa [14]

D.) 15/6

- 3 times 52 = 156, and since you can't exactly convert it to a fraction then i'm assuming that it is 'D'.

- Ouma :>

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3 years ago

Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p

kvv77 [185]

The question is an illustration of composite functions.

Functions c(n) and h(n) are $\mathbf{c(n) = 5000 + 250n}$ and $\mathbf{n(h) = 5h}$
The composite function c(n(h)) is $\mathbf{c(n(h)) = 5000 + 1250h}$
The value of c(n(100)) is $\mathbf{c(n(100)) = 130000}$
The interpretation is: <em>"the cost of working for 100 hours is $130000"</em>

The given parameters are:

$5000 in fixed costs plus an additional $250
5 systems in one hour of production

<u>(a) Functions c(n) and n(h)</u>

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

$\mathbf{c(n) = Fixed + Additional \times n}$

This gives

$\mathbf{c(n) = 5000 + 250 \times n}$

$\mathbf{c(n) = 5000 + 250n}$

The function for number of systems is:

$\mathbf{n(h) = 5 \times h}$

$\mathbf{n(h) = 5h}$

<u>(b) Function c(n(h))</u>

In (a), we have:

$\mathbf{c(n) = 5000 + 250n}$

$\mathbf{n(h) = 5h}$

Substitute n(h) for n in $\mathbf{c(n) = 5000 + 250n}$

$\mathbf{c(n(h)) = 5000 + 250n(h)}$

Substitute $\mathbf{n(h) = 5h}$

$\mathbf{c(n(h)) = 5000 + 250 \times 5h}$

$\mathbf{c(n(h)) = 5000 + 1250h}$

<u>(c) Find c(n(100))</u>

c(n(100)) means that h = 100.

So, we have:

$\mathbf{c(n(100)) = 5000 + 1250 \times 100}$

$\mathbf{c(n(100)) = 5000 + 125000}$

$\mathbf{c(n(100)) = 130000}$

<u>(d) Interpret (c)</u>

In (c), we have: $\mathbf{c(n(100)) = 130000}$

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

5 0

3 years ago

Chris used 43.96 feet of fencing to enclose a circular garden. What is the radius, in feet, of the garden?

UNO [17]

Answer:

r = 7 ft

Step-by-step explanation:

The circumference (C) of a circle is calculated as

C = 2πr ( r is the radius )

Here C = 43.96 , then

2πr = 43.96 ( divide both sides by 2 × 3.14 ← for π )

r = $\frac{43.96}{2(3.14)}$ = $\frac{43.96}{6.28}$ = 7 ft

4 0

2 years ago