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vazorg [7]
3 years ago
5

SIMPLIFY RADICAL 5√11×12√110

Mathematics
1 answer:
Aliun [14]3 years ago
7 0
Well, to simplify a radical, you would multiply inside the radical and outside. 

So, 60 * root 1210.

Because 1210 divided by 121 (11*11) is 10, we can rewrite this as 660 * root 10. 
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If y varies directly as x and y=35 when x=7, find y when x=11
sveta [45]
Y=kx
35=7k
35/7=k
k=5

y=5x
y=5×11
y=55
3 0
3 years ago
Factories fully. X to the power of three - x
spayn [35]

The expression x³ - x when factored out is x(x -1)(x + 1)

<h3>How to determine the factored expression?</h3>

From the question, we have the following expression that can be used in our computation:

X to the power of three - x

Express the expression properly

So, we have the following representation

x³ - x

The terms of the above expression are:

x³ and x

And the factor of x³ and x

Factor = x

So, we divide x³ and x by x

The results of these divisions are

x³/x = x²

x/x = 1

So, we have the following results

(x³ - x) = x(x² -1)

Express x² -1 as a difference of two squares

So, we have

(x³ - x) = x(x -1)(x + 1)

Hence, the factored expression is x(x -1)(x + 1)

Read more about expressions at

brainly.com/question/18631189

#SPJ1

7 0
1 year ago
10. Given that the total distance travelled is 4 km and that the initial aceleration is 4 m/s², find:a) the value of V.b) the va
andrezito [222]

The initial deceleration is 4 m/s^2, so this means that considering the first line segment, \frac{V-100}{T}=-4 \implies V=100-4T.

The total distance traveled is 4 km, which is equal to 4000 meters. This is equal to the area under the graph, so 400T-\frac{1}{2}(100-V)(5T)=4000.

400(100-4T)-\frac{1}{2}(4T)(5T)=4000\\\\40000-1600T-10T^2=4000\\\\10T^2 +1600T-36000=0\\\\T^2 +160T-3600=0\\\\(T+180)(T-20)=0\\\\T=20 (T > 0)\\\\\therefore V=100-4(20)=20

6 0
1 year ago
How many nanoseconds does it take for a computer to perform one calculation if it performs calculations per second?
igor_vitrenko [27]

I believe the correct question is:

6.7*10^7 calc/sec?

 

So:

1/(6.7 x 10^7) = seconds per calculation

1/(6.7 x 10^7) = 100/(6.7 x 10^9) = 14.9 x 10^-9 seconds per calculation = 14.9 ns

Which is approximately 15 ns

 

Answer:

15 ns

7 0
3 years ago
Daniel read 3 books in 2.5 weeks. Which rate represents this situation?
Nady [450]
The answer is C: 3 books, 2.5 weeks.
3 0
3 years ago
Read 2 more answers
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