Answer:
I think the answer for the first one is 3 I am not sure about the second one
Answer:
61.64 cm
Step-by-step explanation:
The longest metal rod which could be stored in a rectangular box will be equal to its diagonal:
First add 10 on both sides. So it will be v = 1.
Yes. Changing the the word problem into a function, you get 30x=y.
30 = Fixed Length
x = width
y = area
No matter what width (x) you choose, the area (y) is going to be a multiple of 30 (the fixed length) because with two numbers being multiplied, if there is a fixed number that will always be the multiple and not the multiplier. For example, 10 multiplied by every number 1-10 is going to be a multiple of 10.
10x1=10, 10x2=20, 10x3=30, etc
So if Tom chooses any of these widths (x) 5, 10, or 15, y (the area) will be a multiple of 30.
30(5)=150
30(10)=300
30(15)=450
So as we double 5 to get 10, our outcome is doubled 150 to 300 and so forth. Hope this helps.
The answer for t is 46.0416
