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horsena [70]
3 years ago
13

When you measure the length of an object to the eighth of an inch and again to the fourth of an inch, which measurement is more

precise? Explain your answer.
Mathematics
1 answer:
brilliants [131]3 years ago
8 0

The smaller the value of the least increment, the more precise a number is.

Length measured to the nearest 1/8 inch will be more precisely specified than length measured to the nearest 1/4 inch.

_____

In general, <em>precision</em> has little to do with <em>accuracy</em>—how close the measured value is to the actual value. A measurement can be very precise, but just plain wrong. (Many electronic instruments have resolution (precision) that exceeds their accuracy. That is, one or two (or more) of the least-significant displayed digits may be in error.)

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21. For the following exercises, use the descriptions of each pair of lines given below to find the slopes of Line 1 and Line 2.
dybincka [34]

Answer:

The given lines are perpendicular.

Step-by-step explanation:

In the question, two lines are given as line 1 passes through (1,7) and (5,5). Whereas, line 2 passes through (-1,-3) and (1,1).

It is required to find the slope of given lines and figure out whether they are perpendicular, parallel or neither.

To solve this question, first find the slope of both lines. Check if their product is equal to -1, then they are perpendicular. If the slopes are equal the lines are parallel.

Step 1 of 2

Find the slope of first line.

$$\begin{aligned}m_{1} &=\frac{5-7}{5-1} \\m_{1} &=\frac{-2}{4} \\m_{1} &=-\frac{1}{2}\end{aligned}$$

Step 2 of 2

Find the slope of first line.

$$\begin{aligned}&m_{2}=\frac{1-(-3)}{1-(-1)} \\&m_{2}=\frac{4}{2} \\&m_{2}=2\end{aligned}$$

And

$$\begin{aligned}&m_{1} m_{2}=-\frac{1}{2}(2) \\&m_{1} m_{2}=-1\end{aligned}$$

Since, both slopes are reciprocal of each other.

Therefore, the lines are perpendicular.

6 0
2 years ago
Write a blue print of a room a blueprint of a room drawn in a coordinate plane, using an appropriate scale – (out of 4)
svetoff [14.1K]
What your going to want to do is take graph paper each square is five feet draw whatever shape your room is on it and take perimeter and area I cant write the reflection as I don't know what room you have drawn. 
8 0
3 years ago
HELP PLEASE I DON'T UNDERSTAND THIS AT ALL​
Misha Larkins [42]

Answer:

PV/nR = T

Step-by-step explanation:

PV = nRT

Divide each side by nR

PV/nR = nRT/ nR

PV/nR = T

8 0
3 years ago
Read 2 more answers
Using the properties of exponents and logarithms, find the value of x in 19 + 2 ln x = 25.
REY [17]
19+2\ln x=25\ \ \ |-19\\\\2\ln x=6\ \ \ |:2\\\\\ln x=3\iff x=e^3

\text{Used de.finition of the logarithm:}\ \ \ \log_ab=c\iff a^c=b



8 0
3 years ago
Read 2 more answers
I don't know how to solve it.
Nataly [62]

Step-by-step explanation:

Take the first derivative

\frac{d}{dx} ( {x}^{3}  - 3x)

3 {x}^{2}  - 3

Set the derivative equal to 0.

3 {x}^{2}  - 3 = 0

3 {x}^{2}  = 3

{x}^{2}  = 1

x = 1

or

x =  - 1

For any number less than -1, the derivative function will have a Positve number thus a Positve slope for f(x).

For any number, between -1 and 1, the derivative slope will have a negative , thus a negative slope.

Since we are going to Positve to negative slope, we have a local max at x=-1

Plug in -1 for x into the original function

( - 1) {}^{3}  - 3(  - 1) = 2

So the local max is 2 and occurs at x=-1,

For any number greater than 1, we have a Positve number for the derivative function we have a Positve slope.

Since we are going to decreasing to increasing, we have minimum at x=1,

Plug in 1 for x into original function

{1}^{3}   - 3(1)

1 - 3 =  - 2

So the local min occurs at -2, at x=1

8 0
2 years ago
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