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nirvana33 [79]
3 years ago
8

Amanda's first four test scores are 77, 95, 84, and 69. What does Amanda need to score on the next test to have at least an 82 a

verage?
A) 85 or greater
B) 90 or greater
C) greater than 85
D) greater than 92
Mathematics
1 answer:
Anon25 [30]3 years ago
7 0
Add all 5 numbers together then divide it by five and that will give you your answer
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6 0
3 years ago
Read 2 more answers
The perimeter of a rectangular banner is 72 inches. The width of the banner is 1/3 its length. What is the area of the banner?
muminat

Answer:

144

Step-by-step explanation:

If you multiply 4 by 12, then add 100, you get 144 which is the area.

4 0
2 years ago
Is 56 inches less than 5 feet? PLEASE THIS IS AN EMERGENCY! 40 POINTS IF YOU ANSWER! :D
Elena-2011 [213]

Answer:

5ft. = 60 in. so yes, 5 feet is more than 56 inches

Step-by-step explanation:

1 ft. = 12 in. , so 5ft. = 60 in.

7 0
2 years ago
Read 2 more answers
A​ half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches. Assume that the heights of​
Ainat [17]

Answer:

99.5% of all samples of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches.

Step-by-step explanation:

We are given that a half-century ago, the mean height of women in a particular country in their 20's was 64.7 inches. Assume that the heights of​ today's women in their 20's are approximately normally distributed with a standard deviation of 2.07 inches.

Also, a samples of 21 of​ today's women in their 20's have been taken.

<u><em /></u>

<u><em>Let </em></u>\bar X<u><em> = sample mean heights</em></u>

The z-score probability distribution for sample mean is given by;

                          Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean height of women = 64.7 inches

            \sigma = standard deviation = 2.07 inches

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches is given by = P(\bar X \geq 65.86 inches)

  P(\bar X \geq 65.86 inches) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{65.86-64.7}{\frac{2.07}{\sqrt{21} } } ) = P(Z \geq -2.57) = P(Z \leq 2.57)

                                                                        = <u>0.99492  or  99.5%</u>

<em>The above probability is calculated by looking at the value of x = 2.57 in the z table which has an area of 0.99492.</em>

<em />

Therefore, 99.5% of all samples of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches.

3 0
3 years ago
Help me please..............
larisa [96]

Answer:

a.)48

b.)528

c.)448

Step-by-step explanation:

a.)8x8=64. 4x4=16 64-16=48

b.)48(from a. answer)x11=528

c.)11x8(x2 for the other side)=176. 11x4x4=176.

48x2=96. 176+176+96=448

3 0
3 years ago
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