The two numbers are 8 and 12.
When added, you get a sum of 20.
When multiplied, you get a product of 96.
Answer:
-15a² -14a+16
Step-by-step explanation:
<h2>(2-3a)(8+5a)</h2>
2×8=16
2×5a=10a
-3a×8=-24a
-3a×5a=-15a²
16+10a-24a-15a² = -15a² -14a+16
Answer:
Option B.
Step-by-step explanation:
We need to find the range of numbers is most appropriate for the y-axis scale and interval on a graph for given table.
From the given table it is clear that the minimum value of y is 10 and the maximum value of y is 34.
It means 10 and 34 must be included in the Range.
In option C and D 34 in not included in the range, so these options are incorrect.
In option A, 10 is the minimum value of range and interval of 10 is not possible for the range 10-35, because it contains only multiple of 10 on the y-axis. So, this option is incorrect.
In option B, both 10 and 34 are included and interval of 5 is possible for range 0-35.
Therefore, the correct option is B.
Answer:
B) 4% of 52
Step-by-step explanation:
A) 0.25 x 52 = 13
B) 4% of 52 = 0.04 x 42 = 2.08
C) 52 ÷ 4 = 13
D) 52/4 = 13
we know that
If the point belongs to the graph, then the point must satisfy the equation
we will proceed to verify each case
<u>case A.)</u>
The point is
Verify if the point satisfy the equation
For find the value of y in the equation and compare with the y-coordinate of the point
therefore
the equation not passes through the point
<u>case B.)</u>
The point is
Verify if the point satisfy the equation
For find the value of y in the equation and compare with the y-coordinate of the point
therefore
the equation passes through the point
<u>case C.)</u>
The point is
Verify if the point satisfy the equation
For find the value of y in the equation and compare with the y-coordinate of the point
therefore
the equation not passes through the point
<u>case D.)</u>
The point is
Verify if the point satisfy the equation
For find the value of y in the equation and compare with the y-coordinate of the point
therefore
the equation passes through the point
therefore
<u>the answer is</u>