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2 years ago

The ratio of students to faculty members in high school is 23:5. If there are 80 faculty members, how many students are there

Mathematics

1 answer:

Rzqust [24]2 years ago

7 0

Answer: 368

Step-by-step explanation: 80 divided by 5 is 16, so you would use 16 to find out how many students there are. To do that, you have to do 23 times 16, which is 368. Hope this helps!

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Amy, Bodie, Claire, and Dejan are in the same math class. The locations of their desks in relation to each other are graphed on

Xelga [282]

Answer:10 ft

Step-by-step explanation:

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2 years ago

Help!!! Find the distance between the pair of points

coldgirl [10]

Step-by-step explanation:

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2 years ago

I really need help i i put a picture up but this thing do´s not let me post it with out a question ?

kobusy [5.1K]

Answer:

Step-by-step explanation:

$y=-x^{2} -5x-6$

$y=-(x^2+5x+6)$

$y=-(x+3)(x+2)$

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2 years ago

Function h models an object's height in feet after x seconds have passed. Which equation shows that the object's height increase

ASHA 777 [7]

Answer:

Step-by-step explanation:

We know that function h represents an object's height in feet after x seconds.

In that case, option A) h(15) = 100 means that after 15 seconds, the object's height is 100 feet.

Option B) h(100) = 15 means that after 100 seconds, the object's height is 15 meters.

Therefore, neither A nor B are correct.

Option C) h(15) - h(0) = 100 means that between the zeroth and 15th second, their difference is 100 feet.

In other words, the object's height increased by 100 feet over the first 15-second period.

Option C is correct.

For Option D), it gives us the average rate of change. (h(15) - h(0)) / (15) = 100 means that for the first fifteen seconds, the height of the object increased at an average rate of 100 feet per second.

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2 years ago

We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure

STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be $h(t) = -16\cdot t^{2} + 128\cdot t + 320$ , the first and second derivatives are, respectively:

First Derivative

$h'(t) = -32\cdot t +128$

Second Derivative

$h''(t) = -32$

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

$-32\cdot t +128 = 0$

$t = \frac{128}{32}\,s$

$t = 4\,s$ (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

$h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320$

$h(4\,s) = 576\,ft$

The highest altitude that the object reaches is 576 feet.

6 0

3 years ago