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3 years ago

The ratio of students to faculty members in high school is 23:5. If there are 80 faculty members, how many students are there

Mathematics

1 answer:

Rzqust [24]3 years ago

7 0

Answer: 368

Step-by-step explanation: 80 divided by 5 is 16, so you would use 16 to find out how many students there are. To do that, you have to do 23 times 16, which is 368. Hope this helps!

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Find c. Select the letter of the solution.

OlgaM077 [116]

Answer:140

Step-by-step explanation:

4 0

2 years ago

If fx = 2x^2 + 3 and g(x) = x^2 - 7 find (f - g) (x)

Semmy [17]

(f-g) (x) means to subtract g(x) from f(x)

F(x) = 2x^2 +3

g(x) = x^2

This becomes:

2x^2 + 3 - x^2 = x^2 +3

3 0

3 years ago

Consider the equation below. f(x) = 2x3 + 3x2 − 336x (a) Find the interval on which f is increasing. (Enter your answer in inter

Vaselesa [24]

We have been given a function $f(x)=2x^3+3x^2-336x$ . We are asked to find the interval on which function is increasing and decreasing.

(a). First of all, we will find the critical points of function by equating derivative with 0.

$f'(x)=2(3)x^{2}+3(2)x^1-336$

$f'(x)=6x^{2}+6x-336$

$6x^{2}+6x-336=0$

$x^{2}+x-56=0$

$x^{2}+8x-7x-56=0$

$(x+8)-7(x+8)=0$

$(x+8)(x-7)=0$

$x=-8,x=7$

So $x=-8,7$ are critical points and these will divide our function in 3 intervals $(-\infty,-8)U(-8,7)U(7,\infty)$ .

Now we will find derivative over each interval as:

$f'(x)=(x+8)(x-7)$

$f'(-9)=(-9+8)(-9-7)=(-1)(-16)=16$

Since $f'(9)>0$ , therefore, function is increasing on interval $(-\infty,-8)$ .

$f'(x)=(x+8)(x-7)$

$f'(1)=(1+8)(1-7)=(9)(-6)=-54$

Since $f'(1)$ , therefore, function is decreasing on interval $(-8,7)$ .

Let us check for the derivative at $x=8$ .

$f'(x)=(x+8)(x-7)$

$f'(8)=(8+8)(8-7)=(16)(1)=16$

Since $f'(8)>0$ , therefore, function is increasing on interval $(7,\infty)$ .

(b) Since $x=-8,7$ are critical points, so these will be either a maximum or minimum.

Let us find values of f(x) on these two points.

$f(-8)=2(-8)^3+3(-8)^2-336(-8)$

$f(-8)=1856$

$f(7)=2(7)^3+3(7)^2-336(7)$

$f(7)=-1519$

Therefore, $(-8,1856)$ is a local maximum and $(7,-1519)$ is a local minimum.

Let us find 2nd derivative.

$f''(x)=6(2)x^{1}+6$

$f''(x)=12x+6$

$12x+6=0$

$12x=-6$

$\frac{12x}{12}=-\frac{6}{12}$

$x=-\frac{1}{2}$

Therefore, $x=-\frac{1}{2}$ is an inflection point of given function.

3 0

3 years ago

Which of the following measurements results in the largest circle?

AnnZ [28]

Answer:

Step-by-step explanation:

A) r = 8

B) r = 4

C) r = $\sqrt{\frac{30}{\pi } }$ ~ 3.09

D) r = $\frac{30}{2\pi} = \frac{15}{\pi } ~ 4.77$

Circle A has the largest radius, and thus is the largest circle

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2 years ago

Select the histogram that represents the given high temperatures.

Alisiya [41]

Step-by-step explanation:

Step 1: On the horizontal axis, we can choose the scale to be 1 unit = 11 lb.Since the weights in the table start from 65, not from 0, we give a break/kink on the X-axis. Step 2: On the vertical axis, the frequencies are varying from 4 to 10.Thus, we choose the scale to be 1 unit = 2.

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3 years ago