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Firdavs [7]
2 years ago
7

Given PQRS is a square, solve for x.

Mathematics
2 answers:
ivanzaharov [21]2 years ago
7 0

Answer:

x = 11

Step-by-step explanation:

The angles in a square are right , that is 90°

The diagonals bisect the angles , then

6x - 21 = 45 ( add 21 to both sides )

6x = 66 ( divide both sides by 6 )

x = 11

siniylev [52]2 years ago
6 0

Step-by-step explanation:

In the given figure, we can see that there is a square, and know that diagonals of squares bisect each other at 90° , so

Angle PTQ = 90°

( since they bisects each other at 90° )

now,

since the diagonals of the square are equal and they are bisected by each other so,

PT = TQ

then, Angle TPQ = Angle TQP

( since, PT = TQ , Opposite sides are equal )

In triangle PTQ ,

Angle TQP + Angle TPQ + Angle PTQ = 180°

( since, sum of all interior angles of a triangle is 180° )

=》Angle TQP + Angle TPQ + 90° = 180°

( PTQ = 90° )

=》2 × Angle TQP = 90°

( TPQ = TQP )

=》TQP = 45°

From here,

TQP = 45° = 6x - 21

=》6x - 21 = 45°

=》6x = 45 + 21

=》6x = 66

=》x = 66 / 6

=》x = 11

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Vlad1618 [11]

Answer:

true 7x+5y=9

Step-by-step explanation:

7 0
3 years ago
What is the tenth term in the sequence 9, 13, 17, 21, 25…?
Zinaida [17]

Answer:

45

Step-by-step explanation:

9, 13, 17, 21, 25

We are adding 4 each time

9+4 = 13

13+4 =17

17+4 = 21

The common difference =4

a1 = 9

The formula is

an = a1+d(n-1) where n is the term number

an = 9+4(n-1)

We want the 10th term

a10 = 9+4(10-1)

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6 0
3 years ago
Help math homework both questions
-Dominant- [34]

Answer:

Q-12 The vertical length of the top part of elevator to ground is 0.8484 meters .

Q -14 The glide runway path is 24,752.47 feet .

Step-by-step explanation:

Q - 12

Given as :

The diagonal length of the elevator = e = 1.2 meters

The vertical length of the top part of elevator to ground = x meters

The angle made by elevator with ground = Ф = 45°

<u>Now, According to figure</u>

Sin angle = \dfrac{\textrm perpendicular}{\textrm hypotenuse}

Or, Sin Ф = \dfrac{\textrm x}{\textrm e}

Or, Sin 45° =  \dfrac{\textrm x meters}{\textrm 1.2 meters}

Or, 0.707 × 1.2 meters = x

∴ x =  0.8484 meters

So, The vertical length of the top part of elevator to ground = x = 0.8484 meters

Hence,The vertical length of the top part of elevator to ground is 0.8484 meters .  Answer

Q-14

Given as:

The altitude of decent of plane = H = 10,000 feet

The angle of descend =  Ф = 22°

Let the glide runway path = y feet

<u>Now, According to question</u>

Tan angle = \dfrac{\textrm perpendicular}{\textrm base}

Or, Tan Ф = \dfrac{\textrm H}{\textrm y}

Or, Tan 22° =  \dfrac{\textrm  10,000 feet}{\textrm y feet}

Or, 0.4040 =  \dfrac{\textrm  10,000 feet}{\textrm y feet}

Or, y =  \dfrac{\textrm  10,000 feet}{\textrm 0.4040}

∴   y = 24,752.47

So,The glide runway path = y = 24,752.47 feet

Hence, The glide runway path is 24,752.47 feet . Answer

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3 years ago
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The answer is option B

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