Answer:atleast 5 machines
Explanation:
Quantity required (Q) = 3000
Maintainace due = 500 parts
3000 / 500 = 5 = 6 Maintainace
Repair time = 6 × 30 minutes = 300 minutes = 5 hours.
operation time = 5 × 18 × 60 = 5400 minutes
Total operation time = Total operation hours - repair time
5400 - 300 = 5100 hours
For A:
(Standard time × Q) / (reliability × time efficiency × scrap × total working hours)
(3 × 3000) / (. 95×.95×5100)
9000/4602.75 = 1.96
For B:
(Standard time × Q) / (reliability × time efficiency × scrap × total working hours)
(5 × 3000) / (.95×.9×5100)
15000/4360.5 = 3.44
(1.96 + 3.44) = 166.56
=5. 4