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viktelen [127]
2 years ago
14

Which set of ordered pairs does not represent a function

Mathematics
2 answers:
Hoochie [10]2 years ago
8 0
Second one.

The first set of ordered pairs is a function, because no two ordered pairs have the same first coordinates with different second coordinates. The second example is not a function, because it contains the ordered pairs (1,2) and (1,5).
Alex Ar [27]2 years ago
6 0
<h3>Answer:</h3>

The Second one {(-8,-7), (4,-2), (2,9), (-8,8)}

<h3 /><h3>Step-by-step explanation:</h3>

A function only gives ONE out put for a given value. But the second set has two outputs if we input -8, it gives you -7 and 8 so this must not be a function.

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Read 2 more answers
Question 1 (3 points) What value of p makes this equation true? 3p - 8 = -23 . O p = -6 Op = -5 Op = 5 p = 6​
olchik [2.2K]

The value of p that makes the given equation true is equal to: B. p = -5

<u>Given the following equation:</u>

  • 3p - 8 = -23

To find a value of p that makes the given equation true:

In this exercise, you're required to determine a value of p that satisfies the given equation true such that when substituted into the equation, it has a true result or outcome.

Rearranging the equation by collecting like terms, we have:

3p - 8 = -23\\\\3p=-23+8\\\\3p=-15\\\\p=\frac{-15}{3}

p = -5

Find more information: brainly.com/question/3600420

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