Answer:
1/12
Step-by-step explanation:
There are two dices being rolled. A dice has six faces numbered from one to six. A fair dice means that the probability of each number to appear is equal. Thus the probability of any number showing up is:
P(a number appears on the dice) = how much times the number has been displayed on the dice/number of faces of the dice.
Since all numbers appear once, and there are six sides of a dice. therefore:
P(a number appears on the dice) = 1/6. Thus, P(6 appears on a dice) = 1/6.
As far as the odd numbers are concerned, there are three even numbers and three odd numbers on the dice. So P(odd number appears on the dice) = 3/6 = 1/2.
Assuming that the probabilities of both the dices are independent, we can safely multiply both the probabilities. Thus:
P(first dice lands on a 6 and second dice lands on an odd number) = 1/6 * 1/2 = 1/12.
Thus, the final probability is 1/12!!!
To whatttttttttttt free points?
<h3>Given</h3>
right triangle with side "a" = 12 and hypotenuse "c" = 15
<h3>Find</h3>
cos(∠A)
<h3>Solution</h3>
The Pythagorean theorem tells you
... b = √(c² - a²) = √(225 - 144) = √81 = 9
The definition of the cosine tells you
... cos(A) = b/c = 9/15
... cos(A) = 3/5 . . . . . . reduce the fraction
