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4 years ago

Need help asap thanks y'all

Mathematics

2 answers:

Afina-wow [57]4 years ago

8 0

Answer:

It would be 15 cm. because if the triangles are similar then BC = EF

<h2>Please mark me the brainliest!!!</h2>

Vilka [71]4 years ago

5 0

Answer:

what do you need help with?

Step-by-step explanation:

You might be interested in

Amanda is finding 11.2 divided by 14. This is what she got, 14 divided by 11.2 equals 8.0 What is her mistake and fix it. Whats

arsen [322]

Amanda forgot to move the decimal point one place to the left

11.2 / 14 = 0.8

6 0

3 years ago

Suppose that a basketball player can score on a particular shot with probability .3. Use the central limit theorem to find the a

Rom4ik [11]

Answer:

(a) The probability that the number of successes is at most 5 is 0.1379.

(b) The probability that the number of successes is at most 5 is 0.1379.

(d) The probability that the number of successes is at most 11 is 0.9357.

→ All the exact probabilities are more than the approximated probability.

Step-by-step explanation:

Let <em>S</em> = a basketball player scores a shot.

The probability that a basketball player scores a shot is, P (S) = <em>p</em> = 0.30.

The number of sample selected is, <em>n</em> = 25.

The random variable $S\sim Bin(25,0.30)$

According to the central limit theorem if the sample taken from an unknown population is large then the sampling distribution of the sample proportion ( $\hat p$ ) follows a normal distribution.

The mean of the the sampling distribution of the sample proportion is: $E(\hat p)=p=0.30$

The standard deviation of the the sampling distribution of the sample proportion is:

$SD(\hat p)=\sqrt{\frac{ p(1- p)}{n} }=\sqrt{\frac{ 0.30(1-0.30)}{25} }=0.092$

(a)

Compute the probability that the number of successes is at most 5 as follows:

The probability of 5 successes is: $p=\frac{5}{25} =0.20$

$P(\hat p\leq 0.20)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq \frac{0.20-0.30}{0.092} )\\=P(Z\leq -1.087)\\=1-P(Z$

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 5 is 0.1379.

The exact probability that the number of successes is at most 5 is:

$P(S\leq 5)={25\choose 5}(0.30)^{5}91-0.30)^{25-5}=0.1935$

The exact probability is more than the approximated probability.

(b)

Compute the probability that the number of successes is at most 7 as follows:

The probability of 5 successes is: $p=\frac{7}{25} =0.28$

$P(\hat p\leq 0.28)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq \frac{0.28-0.30}{0.092} )\\=P(Z\leq -0.2174)\\=1-P(Z$

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 7 is 0.4129.

The exact probability that the number of successes is at most 7 is:

$P(S\leq 57)={25\choose 7}(0.30)^{7}91-0.30)^{25-7}=0.5118$

The exact probability is more than the approximated probability.

(c)

Compute the probability that the number of successes is at most 9 as follows:

The probability of 5 successes is: $p=\frac{9}{25} =0.36$

$P(\hat p\leq 0.36)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq \frac{0.36-0.30}{0.092} )\\=P(Z\leq 0.6522)\\=0.7422$

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 9 is 0.7422.

The exact probability that the number of successes is at most 9 is:

$P(S\leq 9)={25\choose 9}(0.30)^{9}91-0.30)^{25-9}=0.8106$

The exact probability is more than the approximated probability.

(d)

Compute the probability that the number of successes is at most 11 as follows:

The probability of 5 successes is: $p=\frac{11}{25} =0.44$

$P(\hat p\leq 0.44)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq \frac{0.44-0.30}{0.092} )\\=P(Z\leq 1.522)\\=0.9357$

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 11 is 0.9357.

The exact probability that the number of successes is at most 11 is:

$P(S\leq 11)={25\choose 11}(0.30)^{11}91-0.30)^{25-11}=0.9558$

The exact probability is more than the approximated probability.

6 0

4 years ago

Use the PARTITIONING strategy to solve these, don’t give random answers and actually use the P strategy please! take your time a

Dimas [21]

When we are partitioning in division, we are dividing the number into its place values, and then applying the divisor to each of the values.

For example in the first problem, we have 642, which is also 600 + 40 + 2.

That means we'll have three division problems.

600 ÷ 2 = 300

40 ÷ 2 = 20

2 ÷ 2 = 1

Which means that 642 ÷ 2 = 300 + 20 + 1, or 321.

You can apply this format to the other two problems to find their answers.

If you do, you should get that 969 ÷ 3 = 323, and 844 ÷ 4 = 211.

Hope this helps!

8 0

3 years ago

In 2009, the national debt of a government was about $10.5 trillion. Using 308.0 million as the population for that year, abo

Katarina [22]

Answer:

34091 dollars per person

Step-by-step explanation:

In order to answer the question, you have to divide the amount of debt by the amount of population to obtain the amount of dollars per person.

The debt was $10.5 trillion. A trillion is a thousand billion (1000 multiplied by a billion which is $10^{9}$ in scientific notation)

1000= $10^{3}$

One trillion is $(10^{3})(10^{9})=10^{12}$

The debt is: $ 10.5 x $10^{12}$

The population is scientific notation is: 308.0 x $10^{6}$

Dividing the amount of debt by the amount of population:

$\frac{(10.5)(10^{12})}{(308.0)(10^{6})}=\frac{(10.5)(10^{12-6})}{308.0}=\frac{(10.5)(10^{6})}{308.0}$

Simplifying and expressing it in standard notation:

34090.9 dollars per person

Rounding to the nearest dollar:

34091 dollars per person.

4 0

3 years ago

What is 7) 4x -2(3x + 7) <br>

lapo4ka [179]

4x -2(3x+7)

Use the distributive property:

4x - 6x -14

Combine like terms:

-2x - 14

4 0

4 years ago