There is one critical point at (2, 4), but this point happens to fall on one of the boundaries of the region. We'll get to that point in a moment.
Along the boundary 
, we have
which attains a maximum value of
Along 
, we have
which attains a maximum of
Along 
, we have
which attains a maximum of
So over the given region, the absolute maximum of 
is 1578 at (2, 44).
The correct answer is one
good luck in math
Answer:
y=-5x-3
Step-by-step explanation:
Slope: -5/1 =-5
Y2-Y1/X2-X1=2-7/1-2=-5/1
Y-intercept: -3
Answer:
C. 3.5 mi
Step-by-step explanation:
Reference angle = angle of elevation
Angle of elevation = angle of depression = 6° (alternate angle theorem)
Hypotenuse = x
Opposite = 1905 ft
Apply trigonometric function SOH:
Sin 6° = Opp/Hyp
Sin 6° = 1905/x
x * Sin 6° = 1905
x = 1905/Sin 6°
x = 18,224.7 ft
Convert form feet to miles
1 mi = 5,280 ft
Therefore,
18,224.7 = 18,224.7/5,280
= 3.45164773 mi
≈ 3.5 mi (nearest mile)
Its factors would be
(x+2)*(x-1)*(x+0)
x^2 +x -2
x^3 + 0 + x^2 + 0 -2x +0
Equation: x^3 + x^2 -2x
f(2) = 8 + 4 -4
2x^3 + 2x^2 -4x +0
f(2) = 16 + 8 -8
3x^3 + 3x^2 -6x +0
f(2) = 24 +12 -12
4x^3 + 4x^2 -8x +0
f(2) = 32 +16 -16
So, the equation is:
4x^3 + 4x^2 -8x = 0
