Anybody know this answer

I forgot how I check to see if my answer is right :,) can anyone help me ;v; The answer is right I just forgot how to check it

Novosadov [1.4K]

Answer:

see below

Step-by-step explanation:

To check your solution , plug the value of k into the original equation

6(7k-10) =24

k=2

6(7*2-10) =24

6(14-10) =24

6(4) =24

24=24

The solution is correct

3 0

2 years ago

Choose the value of x that makes the open sentence true 40-x^2 < 2x+15.

S_A_V [24]

I believe the answer is B, but I'm not 100% sure. :)

6 0

3 years ago

Read 2 more answers

State whether f is a function

Alenkinab [10]

<h2>Answer:</h2>

$y=\pm (\frac{x}{6})^{\frac{1}{4}} \ is \ not \ a \ function$

<h2>Step by step solution:</h2>

A function $f$ from a set $A$ to a set $B$ is a relation that assigns to each element $x$ in the set $A$ exactly one element $y$ in the set $B$ . The set $A$ is the domain (also called the set of inputs) of the function and the set $B$ contains the range (also called the set of outputs). On the other hand, a function has an inverse function if and only if passes the Horizontal Line Test for Inverse Functions. This test tells us that a function $f$ has an inverse function if and only if there is no any horizontal line that intersects the graph of $f$ at more than one point. So the function is called one-to-one. The graph of $f$ is shown below. As you can see, this function does not pass the Horizontal Line Test, therefore the inverse is not a function. However, let's find $f^-{1}(x)$ :

$f(x)=6x^4 \\ \\ Substitute \ f(x) \ by \ y \\ \\ y=6x^4 \\ \\ Interchange \ x \ and \ y: \\ \\ x=6y^4 \\ \\ Solve \ for \ y: \\ \\ y^4=\frac{x}{6} \\ \\ Solving \\ \\y=\pm \sqrt[4]{\frac{x}{6}} \\ \\ \boxed{y=\pm \left(\frac{x}{6}\right)^{\frac{1}{4}}}$