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3 years ago

7

You.have at most $8 to buy lunch. Sandwiches cost $4 each, drinks cost $1.50 each, and cookies cost $0.75 each. If you buy a san

dwich and a drink, how many cookies can you buy?

2 answers:

lina2011 [118]3 years ago

8 0

You are able to purchase 2 cookies :)

abruzzese [7]3 years ago

5 0

Answer:

you can buy 2 cookies

Step-by-step explanation:

4+1.5=5.5

8-5.5=1.5

1.5/.75=2

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Baker, Inc. uses the sum-of-the-years’-digits method to depreciate a $79,600.00 piece of equipment that has an estimated life of

Anastasy [175]

The book value at the end of year 2 of the equipment depreciated using the sum-of-the-years’-digits method is $65,560.

<h3>What is the book value at the end of year 2? </h3>

Depreciation is a method used to expense the cost of an asset. Book value is the cost of the asset less the accumulated depreciation.

Sum-of-the-year digits = (remaining useful life / sum of the years ) x (Cost of asset - Salvage value)

Depreciation expense in year 1:

Sum of the years = 1 +2 +3 +4 + 5 + 6 + 7 + 8 + 9 + 10+ 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 210

Undepreciated life of the asset = 20

(20 / 210) x ($79,600 - 4,000) = 7200

Depreciation expense in year 2:

19 / 210 x ($79,600 - 4,000) = 6840

Book value = 79600 - 7200 - 6840 = $65,560

To learn more about depreciation, please check: brainly.com/question/25552427

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2 years ago

What is 0.42 in a fraction in simplest form

RideAnS [48]

0.42 equals

- 42/100

- 21/50

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Rhonda has $315 in her saving account. She wants to save at least $585. Write and

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Step-by-step explanation:

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3 years ago

The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time

cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

$1\leq t\geq \sqrt{2}$

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

$h =20-5t^{2}$ -----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height $h = 15m$

Put height value in equation 1

$15 =20-5t^{2}$

$5t^{2} =20-15$

$5t^{2} =5$

$t^{2} =1$

$t =\pm1$

We know that the time is always positive, therefore $t=1$

when the stuntman is 10m above the ground.

height $h = 10m$

Put height value in equation 1

$10 =20-5t^{2}$

$5t^{2} =20-10$

$5t^{2} =10$

$t^{2} =\frac{10}{5}$

$t^{2} =2$

$t=\pm\sqrt{2}$

$t=\sqrt{2}$

Therefore ,time interval of camera film him is $1\leq t\geq \sqrt{2}$

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Step-by-step explanation:

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