Answer:
Step 3: Choice D
Step 5: Choice B
Step 6: Choice A
Step 8: Choice C
(I saw in the top left corner of the picture that this is for Algebra II. I am in 8th grade, currently taking geometry, and I haven't taken Algebra II yet, but I <em>did</em> take Algebra I last year. I am 95% sure this is correct but if it isn't, the I sincerely apologize.)
Answer:
The side length of the large square is √2 times larger than the side length of the small square.
Step-by-step explanation:
Suppose we have a small square (square 1) and a large square (square 2). The area of the large square is twice that of the small square, that is,
A₂ = 2 A₁
A₂/A₁ = 2 [1]
The area of a square is equal to the length of the side (l) raised to the second power.
A = l²
l = √A
The ratio of l₂ to l₁ is:
l₂/l₁ = √A₂ / √A₁ = √(A₂/A₁)
We can replace [1] in the previous expression.
l₂/l₁ = √2
The side length of the large square is √2 times larger than the side length of the small square.
Answer:
The concluding part
Step-by-step explanation: