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RideAnS [48]
2 years ago
14

What is the range of this function?

Mathematics
1 answer:
AnnyKZ [126]2 years ago
6 0

Answer:

Range {6, 7, 9, 14, 15}

Step-by-step explanation:

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Evaluate the following expression 30x^2y x=-2/5 y=5/8
meriva
30(-2/5)²(5/8) = 30*(4/25)*(5/8) = 30*4/(5*8) = 3

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3 years ago
Rút gọn<br> Giúp em với ạ. em lm mãi ko ra
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Answer:

Step-by-step 12explanation:

12

5 0
3 years ago
Read 2 more answers
Question in attached file
Dovator [93]
13 is C, √10
Rational numbers are numbers that can be expressed as a ratio, or a fraction.


14 is C, 9.5 × 10^5 
7 0
3 years ago
A rectangle has a length of 9.00 inches and a width of 4.25 inches. What is the area in square inches? Round to the correct sign
ale4655 [162]
Area of rectangle = length x breadth
= 9 x 4.25
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Hope this helps you!
5 0
2 years ago
a normal distribution with a mean of 25 minutes with a population standard deviation of 5 minutes. The store manager sampled 100
sergiy2304 [10]

Answer:

z=\frac{24.25-25}{\frac{5}{\sqrt{100}}}=-1.5      

The p value for this case would be given with this probability:

p_v =P(z  

For this case since the p value is higher than the significance level of 0.01 we have enough evidence to fail to reject the null hypothesis and we don't have enough evidence to conclude that the true mean is significantly less than 25 min.

Step-by-step explanation:

Information given

\bar X=242.5 represent the sample mean      

\sigma=5 represent the population deviation

n=100 sample size      

\mu_o =25 represent the value to check

\alpha=0.01 represent the significance level

z would represent the statistic  

p_v represent the p value

Hypotheis to test

We want to verify if the true mean is less than 25 min, the system of hypothesis would be:      

Null hypothesis:\mu \geq 25      

Alternative hypothesis:\mu < 25      

The statistic would be given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)      

And replacing the info given we got:

z=\frac{24.25-25}{\frac{5}{\sqrt{100}}}=-1.5      

The p value for this case would be given with this probability:

p_v =P(z  

For this case since the p value is higher than the significance level of 0.01 we have enough evidence to fail to reject the null hypothesis and we don't have enough evidence to conclude that the true mean is significantly less than 25 min.

4 0
3 years ago
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