Magnetic torquer
or torque rod are essentially sets of electromagnets that are laid out to create a
magnetic field that interfaces with an ambient magnetic field, so that the
counter-forces produced is a stronger magnetic force. In addition, its magnetic
field strength increases with the current due to the rod that has field lines
pointing in the same direction, closed together and nearly parallel with uniformly
spaced. This set up indicates that the field of a torque rod produced powerful
magnetic field than a torque coil.
Answer:
Given: m = 5 kg, r =1 m, ω = 2 radian/s, centripetal force = ?
Formula : Centripetal force = mv²/r = mrω²
(Since v = r ω)
Put the values.
Explanation:
Wind resistance is a kind of friction we usually try to minimize. It makes our cars and planes run less efficiently. At the same time though, we need friction between our tires and the road to move, as well as friction in our brakes to stop. We wouldn't be able to walk without friction, or start a campfire by rubbing sticks together.
B4 the tackle:
<span>The linebacker's momentum = 115 x 8.5 = 977.5 kg m/s north </span>
<span>and the halfback's momentum = 89 x 6.7 = 596.3 kg m/s east </span>
<span>After the tackle they move together with a momentum equal to the vector sum of their separate momentums b4 the tackle </span>
<span>The vector triangle is right angled: </span>
<span>magnitude of final momentum = √(977.5² + 596.3²) = 1145.034 kg m/s </span>
<span>so (115 + 89)v(f) = 1145.034 ←←[b/c p = mv] </span>
<span>v(f) = 5.6 m/s (to 2 sig figs) </span>
<span>direction of v(f) is the same as the direction of the final momentum </span>
<span>so direction of v(f) = arctan (596.3 / 977.5) = N 31° E (to 2 sig figs) </span>
<span>so the velocity of the two players after the tackle is 5.6 m/s in the direction N 31° E </span>
<span>btw ... The direction can be given heaps of different ways ... N 31° E is probably the easiest way to express it when using the vector triangle to find it</span>
The correct answer is A. B. C. Hope this helps!!