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katrin2010 [14]
3 years ago
11

What is the solution to 2x^2 + X - 1 = 2

Mathematics
2 answers:
Maru [420]3 years ago
8 0

Answer: x = square root of -x + 3 / 2

Step-by-step explanation:

2x^2 + x - 1 = 2

add 1 to both sides

2x^2 + x = 3

subtract x from both sides

2x^2 = -x + 3

square root both sides

2x = square root of -x + 3

divide by 2

x = square root of -x + 3 / 2

Naddik [55]3 years ago
4 0

Answer:

Step-by-step explanation:

hello :

2x² + X - 1 = 2

2x² + X - 1 -2 = 2-2

2x² + X - 3 =0

(x-1)(2x+3) =0

x-1=0 or 2x+3 = 0

x =1 or x= -3/2

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Evaluate the piecewise function for the given values.
adoni [48]

Answer:

f(-3) = -2

f(-2.6) = -2

f(0.6) = 2.4

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Step-by-step explanation:

(Whole question:

Evaluate the piecewise function for the given values.

Find f(-3), f(-2,6), f(0.6), and f(4.5) for f(x)={ -2 If x ≤ 0 4x. If 0 <x <1. x + 4. If x ≥ 1)

As the piecewise function shows, the function f(x) has the value of -2 for values of x lesser or equal than 0, has the value of 4x if the value of x is between 0 and 1, and has the value of x+4 for values of x greater or equal than 1.

So, for f(-3), the value of x is lesser than 0, so we have that f(-3) = -2

For f(-2.6), the value of x is lesser than 0, so we have that f(-3) = -2

For f(0.6), the value of x is between 0 and 1, so we have that f(0.6) = 4*0.6 = 2.4

For f(4.5), the value of x is greater than 1, so we have that f(4.5) = 4.5 + 4 = 8.5

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Step-by-step explanation:

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Step-by-step explanation:

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