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Tems11 [23]
3 years ago
8

A right rectangular prism is 1012 m wide, 1512 m long, and 3 m tall.

Mathematics
2 answers:
Olegator [25]3 years ago
7 0
1012 x 1512 x 3 = 4590432 . the only suitable answer would be A<span />
Akimi4 [234]3 years ago
4 0

Answer:

Option (c) is correct.

volume of rectangular prism is 488\frac{1}{4} m³

Step-by-step explanation:

 Given : A right rectangular prism is 10\frac{1}{2} m wide,15\frac{1}{2} m long, and 3 m tall.

We have to find the volume of given rectangular prism .

Volume of rectangular prism is given by the product of its length , width and height.

That is mathematically written as

Volume of rectangular prism = Length × width × height

Given : Length = 10\frac{1}{2} m =\frac{21}{2} m

width = 15\frac{1}{2} = \frac{31}{2}

height =  3 m

Thus, Volume of  rectangular prism = \frac{21}{2}\times \frac{31}{2} \times 3

Simplify, we get,

Volume of  rectangular prism = \frac{1953}{4}=488\frac{1}{4}

Thus, volume of rectangular prism is 488\frac{1}{4} m³

Thus, option (c) is correct.

   

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6.26-2.01\frac{2.47}{\sqrt{50}}=5.56    

6.26+2.01\frac{2.47}{\sqrt{50}}=6.96    

So on this case the 95% confidence interval would be given by (5.56;6.96)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

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The mean calculated for this case is \bar X=6.26

The sample deviation calculated s=2.47

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

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Assuming a Confidence of 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that t_{\alpha/2}=2.01

Now we have everything in order to replace into formula (1):

6.26-2.01\frac{2.47}{\sqrt{50}}=5.56    

6.26+2.01\frac{2.47}{\sqrt{50}}=6.96    

So on this case the 95% confidence interval would be given by (5.56;6.96)    

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