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Tems11 [23]
3 years ago
15

At a used book sale, the number of books bought and the price paid by five different customers is shown in the table below. Odin

knows that there is a linear model that describes the relationship between the number of books bought and the price

Mathematics
1 answer:
Arisa [49]3 years ago
7 0

Answer:

Part A= 0.5

Step-by-step explanation:

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What is the quotient in simplified form ? Need help please
Gre4nikov [31]

Answer:

  -\dfrac{4a^{12}b^8}{5}

Step-by-step explanation:

The applicable rules of exponents are ...

  \dfrac{1}{a^{-b}}=a^b\\\\a^ba^c=a^{b+c}

Your ratio simplifies to ...

  \dfrac{-8a^8b^{-2}}{10a^{-4}b^{-10}}=-\dfrac{4}{5}a^{8-(-4)}b^{-2-(-10)}\\\\=-\dfrac{4a^{12}b^8}{5}

_____

Please note that simplifying the constants, -8/10 to -4/5, eliminates half the answer choices. Since exponents are only multiplied when a power is raised to a power, you can pretty much eliminate the second choice as being unreasonable. ((a^b)^c = a^(bc))

8 0
4 years ago
What is the distance between (2,-9) and (-1,4)
Pepsi [2]

Answer:

34 because

Step-by-step explanation:

Mark brainliest

8 0
2 years ago
A person invested $2,500 in an account growing at a rate allowing the money to
sveta [45]

Answer:

Step-by-step explanation:

A person invested $2,500 in an account growing at a rate allowing the money to double every 11 years. How long, to the nearest tenth of a year would it take for the

value of the account to reach $3,800?

The formula for exponential growth given as:

A(t) = Ao (1/2)^t/t½

A(t) = Amount after time t = $3,800

Ao = Initial amount invested = $2500

t = Time in years

t½ = Time it takes to double = 11 years

Hence,

3800 = 2500(1/2)^t/11

Divide both sides by 2500

3800/2500 = 2500(1/2)^t/11/2500

3 0
3 years ago
Expresión factorizada <br> 12abxyz - 3xyz - 4 ab + 1
BARSIC [14]

Answer:

12+3-4+1=12

Step-by-step explanation:

5 0
3 years ago
Two cars leave at the same time from points A and B, the distance between them is 280 km. If the cars meet each other, they’ll m
kykrilka [37]
Set up the following equations:

2x + 2y = 280

14x - 14y = 280

x represents car A's speed, and y represents car B's speed.

We'll use elimination to solve this system of equations. Multiply the first equation by 7:

(2x + 2y = 280) * 7 = 14x + 14y = 1960

14x - 14y = 280

Combine both equations:

28x = 2240

Divide both sides by 28 to get x by itself:

x = 80

The speed of car A is 80 mph.

Since we now know the value of one of the variables, we can plug it into the first equation:

2(80) + 2y = 280

160 + 2y = 280

Subtract 160 from both sides.

2y = 120

Divide both sides by 2 to get y by itself:

y = 60

The speed of car B is 60 mph.

7 0
4 years ago
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