Answer: 1/11 is the simplified form...
Hope this helps, stay safe :D
Answer:
There were 10 flies originally
Step-by-step explanation:
Since we have an exponential growth, we will be having a constant percentage of increase and we can set up the increase at any day using the following equation;
V = I(1+r)^d
where V is the number of flies on a particular day
I is the initial number of flies
r is the constant increase in percentage
and d is the number of days.
So we have for the second day;
60 = I(1+r)^2 ••••••(i)
For the fourth day, we have;
360 = I(1+r)^4 ••••••••(ii)
divide equation ii by i; we have;
360/60 = (1+r)^4/(1+r)^2
6 = (1+r)^2
(√6)^2 = (1+r)^2
1 + r = √6
r = √6 - 1
So we can substitute the value of r in any of the equations to get I which is the initial number of flies
Let’s use equation 1
60 = I(1 + r)^2
60 = I(1 + √6 -1)^2
60 = I(√6)^2
60 = 6I
I = 60/6
I = 10 flies
Send a better picture so I can help.
Answer:
One approach to this problem is to obtain the graph for the given equation.
We need to find every intersection those functions have with the axis 'x' and 'y'
starting with g(x)
g(x=0)=0-3, first point (0,-3) it iis the crossing point with 'x' axis
g(x)=0=x-3, second point (3,0) it iis the crossing point with 'y' axis
Lets do the same for f(x)
g(x=0)=0, this leads to the first point (0,0) it iis the crossing point with 'x' axis and also, with the 'y' axis
We dont need to find any other, since always y=x
By plotting we have the attached picture
Now you can see that g(x) differs from its parent function in that is shifted 3 units to the right, and also 3 units down.
Step-by-step explanation:
