A man is walking a triangular path, partially represented by the vectors AB−⇀−=⟨0,10⟩ and CA−⇀−=⟨−12,0⟩ . If his distance is rep
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Answer:
(3, -3 8/9)
Step-by-step explanation:
Use a slope calculation or a graph to find the slope of the line.
m = (y-y)/(x-x)
m = (-3- -5)/(7- -2)
m = 2/9
Then write the equation of the line. I used point-slope form. (You could use y=mx+b, slope-intercept form, but you'd have to first calculate b as well)
Point-slope form:
y -Y = m(x-X)
y - -3 = 2/9(x- 7)
y + 3 = 2/9(x - 7)
We know the x-coordinate of the point we're looking for is 3. Fill that in as well and calculate the y that goes with it.
y + 3 = 2/9(3-7)
y+3=2/9(-4)
y = -8/9 - 3
y = -3 8/9
In decimal form this is -3.8888repeating
see image.
The point at x=3 on the line between M(7,-3) and N(-2,-5) is (3, -3 8/9).
