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3 years ago

Which region in the graph below is the solution of the system of inequalities given below?

Mathematics

1 answer:

mote1985 [20]3 years ago

3 0

Answer:

I'm not sure but I think region 3

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Monica’s checkbook register balance is $456.98. She has written checks in the amounts of $10.00, $14.95, $6.07, and $109.10. She

Setler79 [48]

456.98-10-14.95-6.07-109.10-30=<span>286.86

So her new </span>checkbook balance is $286.86

5 0

3 years ago

Find the area of the following figure. Explain how you found your answer.

iragen [17]

Answer:

Below

Step-by-step explanation:

Let's say that each square on the grid represents 1 cm

First find the area of the two triangles

For the larger one: A = bh/2

A = 3 x 3 / 2

= 4.5 cm^2

For the smaller one : A = bh/2

A = 2 x 2 / 2

= 2 cm^2

For the rectangle : A = lw

A = 4 x 5

= 20 cm^2

Add them all up to get the area

4.5 + 2 + 20 = 26.5 cm^2

Hope this helps!

5 0

3 years ago

Read 2 more answers

Expand and simplify: (x-5)(x+5)

stealth61 [152]

X^2-5x+5x-25 (multiply (x-5) with (x+5))
X^2-25 ( -5x+5x =0)

5 0

3 years ago

Read 2 more answers

What is the solution to 3!

AlekseyPX

3! =3 x 2 x 1 = 6

Y!= Y x (y-1) x ... x 1=

4 0

3 years ago

Read 2 more answers

Please show your work and explain it.

Maru [420]

Answer:

$f(x)=\dfrac{x+2}{2(x-2)}$

Step-by-step explanation:

Remember when you divide fractions, you need to get the reciprocal of the divisor and multiply. So your first simplification would be:

$\dfrac{x^2+4x+4}{x^2-6x+8}\div\dfrac{6x+12}{3x-12}\\\\=\dfrac{x^2+4x+4}{x^2-6x+8}\times\dfrac{3x-12}{6x+12}\\\\=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}$

Next we factor what we can so we can further simplify the rest of the equation:

$=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}\\\\=\dfrac{(x+2)(x+2)(3x-12)}{(x^2-6x+8)(6(x+2))}\\\\$

We can now cancel out (x+2)

$=\dfrac{(x+2)(3x-12)}{(x^2-6x+8)(6)}$

Next we factor out even more:

$=\dfrac{(x+2)(3)(x-4)}{(x-2)(x-4)(6)}$

We cancel out x-4 and reduce the 3 and 6 into simpler terms:

$=\dfrac{(x+2)(1)}{(x-2)(2)}$

And we can now simplify it to:

$=\dfrac{x+2}{2(x-2)}$

6 0

3 years ago