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Mekhanik [1.2K]

3 years ago

5

A right triangle has a base equal to 13 inches and a height equal to 18 inches. Find the area of the trlangle.

1 answer:

never [62]3 years ago

3 0

Answer:

117

Step-by-step explanation:

The formula for a triangle is base times hight divided by two. So, 13 x 18 = 234, and 234/2 = 117

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Brennan is planting seeds. He has 1/5 of a pack of seeds and 5 flower pots. What fraction of a pack of seeds will be planted in

Maru [420]

(1/5)/(5)=(1/5)(1/5)=1/25 of a pack of seeds will be planted in each pot

8 0

2 years ago

In Jason's baseball card

serious [3.7K]

Answer:

31

Step-by-step explanation:

50 x 0.62 = 31

3 0

3 years ago

Easy question need fast please

deff fn [24]

Answer:

I cant see the question

Step-by-step explanation:

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6 0

2 years ago

Paulo's economics course requires two papers ? ?one long and one short ? ?throughout the semester. The number of pages, l l, in

mixer [17]

Answer:

27 pages.

Step-by-step explanation:

Let l be the number of pages in the long paper and s be the number of pages in the short paper.

We have been given that the total number of pages for both papers is 40. We can represent this information in an equation as:

$l+s=40...(1)$

We are also told that the number of pages in the long paper is one more than two times the number of pages in the short paper. We can represent this information in an equation as:

$l=2s+1...(2)$

We will use substitution method to solve system of linear equations.

From equation (1) we will get,

$s=40-l$

Upon substituting this value in equation (2) we will get,

$l=2(40-l)+1$

$l=80-2l+1$

Upon adding 2l to both sides of our equation we will get,

$l+2l=80-2l+2l+1$

$l+2l=80+1$

$3l=81$

Let us divide both sides of our equation by 3 we will get,

$\frac{3l}{3}=\frac{81}{3}$

$l=27$

Therefore, there must be 27 pages in the long paper.

8 0

3 years ago

A scientist claims that 7% 7 % of viruses are airborne. If the scientist is accurate, what is the probability that the proportio

Reptile [31]

Answer:

The probability is $P(|p-\^{p}| > 0.03) = 0.0040$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.07$

The mean of the sampling distribution is $\mu_p = 0.07$

The sample size is n = 600

Generally the standard deviation is mathematically represented as

$\sigma_p = \sqrt{\frac{p (1 -p)}{n} }$

=> $\sigma_p = \sqrt{\frac{0.07(1 -0.07)}{600} }$

=> $\sigma_p = 0.010416$

Generally the probability that the proportion of airborne viruses in a sample of 600 viruses would differ from the population proportion by greater than 3% is mathematically represented as

$P(|p-\^{p}| > 0.03) = 1 - P(|p -\^{p}| \le 0.03)$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-0.03 \le p -\^{p} \le 0.03 )$

Now add p to both side of the inequality

=> $P(|p-\^{p}| > 0.03) = 1 - P( 0.07-0.03 \le \^{p} \le 0.03+ 0.07 )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(0.04 \le \^{p} \le 0.10 )$

Now converting the probabilities to their respective standardized score

=> $P(|p-\^{p}| > 0.03) = 1 - P(\frac{0.04 - 0.07}{0.010416} \le Z \le \frac{0.10 -0.07}{0.010416} )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-2.88 \le Z \le 2.88 )$

=> $P(|p-\^{p}| > 0.03) = 1 - [P(Z \le 2.88) - P(Z \le -2.88)]$

From the z-table

$P(Z \le 2.88) = 0.9980$

and

$P(Z \le -2.88) = 0.0020$

So

$P(|p-\^{p}| > 0.03) = 1 - [0.9980 - 0.0020]$

=> $P(|p-\^{p}| > 0.03) = 0.0040$

7 0

3 years ago