All categories

3 years ago

A right triangle has a base equal to 13 inches and a height equal to 18 inches. Find the area of the trlangle.

Mathematics

1 answer:

never [62]3 years ago

3 0

Answer:

117

Step-by-step explanation:

The formula for a triangle is base times hight divided by two. So, 13 x 18 = 234, and 234/2 = 117

You might be interested in

HELP PLEASE!!

Ostrovityanka [42]

Less would be the answer for both i think :P im late XD

5 0

3 years ago

Find parametric equations through point P=(2,2,7) in the direction of the vector v = (44, 14, -20)?

ycow [4]

9514 1404 393

Answer:

(x, y, z) = (2+44t, 2+14t, 7-20t)

Step-by-step explanation:

One way to write parametric equations for line L is ...

L = P + t·<em>v</em>

where P is the given point and <em>v</em> is the given direction vector. Using that form, we have ...

(x, y, z) = (2+44t, 2+14t, 7-20t)

If you like, you can remove a common factor of 2 from the coefficients of t.

(x, y, z) = (2+22t, 2+7t, 7-10t)

5 0

2 years ago

Please help! ASAP will give brainiest

katen-ka-za [31]

I got a decimal,10.66.

8 0

3 years ago

Read 2 more answers

Rewrite c(x) = x^2 + 5x + 2 / x - 3 in the form y = p (x) + r(x)/b(x) where r has degree less than b

MissTica

Answer:

Socratic app it will help you

3 0

3 years ago

Expression for all solutions to the equation cos(theta) = 1 + 3cos(theta)

OleMash [197]

$\cos\theta=1+3\cos\theta\implies 0=1+2\cos\theta\implies \cos\theta=-\dfrac12$

On the unit cirlce, the cosine of an angle is negative whenever the angle falls in the interval $\dfrac\pi2$ .

If you recall your special triangles, this cosine occurs for angles of $x=\dfrac{2\pi}3$ and $x=\dfrac{4\pi}3$ .

More generally, this occurs for $x=\dfrac{2\pi}3+2n\pi$ and $x=\dfrac{4\pi}3+2n\pi$ , where $n$ is an integer.

7 0

3 years ago