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3 years ago

3 ^(1 − 7 x = 7 ^x find the exact value

Mathematics

2 answers:

Shalnov [3]3 years ago

7 0

Answer:

(

)

(

)

(

)

Step-by-step explanation:

wariber [46]3 years ago

3 0

Answer:

= ln ( 3 ) 7 ln ( 3 ) + ln ( 7 )

Step-by-step explanation:

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Find the distance between the following pairs of points: C (1,6) .D (13.41).

worty [1.4K]

The person above is correct

8 0

3 years ago

Foci of ellipse of 3x2 + y2 =9

Oksi-84 [34.3K]

Answer:

x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3

Step-by-step explanation:

Let's solve for x.

3x2+y2=9

Step 1: Add -y^2 to both sides.

3x2+y2+−y2=9+−y2

3x2=−y2+9

Step 2: Divide both sides by 3.

3x^2/3= -y^2+9/3

x^2=-1/3 y^2 +3

x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3

Hope it helped!

8 0

3 years ago

13 points !!-1/4 > 1/2

Brrunno [24]

-1/4 is less then 1/2 because -1/4 is negative and 1/2 is positive and also -1/4 is 25% and 1/2 is 50%

4 0

3 years ago

Can u guys help me with all of those ?'s plz I don't get it

hram777 [196]

I can't see the math problems.

4 0

3 years ago

K=mv^2/2 solve for v

matrenka [14]

Answer: $v=\sqrt[]{\frac{2K}{m} }$

Step-by-step explanation:

$K=\frac{mv^2}{2}$

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;

$2*K=\frac{mv^2}{2}*2$

$2K=mv^2$

Divide by m to isolate $v^2$ .

$\frac{2K}{m}=\frac{mv^2}{m}$

$\frac{2K}{m} =v^2$

To eliminate the square and isolate v, extract the square root.

$\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}$

$\sqrt[]{\frac{2K}{m} }=v$

let's rewrite it in a way that v is in the left side.

$v=\sqrt[]{\frac{2K}{m} }$

4 0

3 years ago