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OLEGan [10]
3 years ago
14

3 ^(1 − 7 x = 7 ^x find the exact value

Mathematics
2 answers:
Shalnov [3]3 years ago
7 0

Answer:

x

=

ln

(

3

)

7

ln

(

3

)

+

ln

(

7

)

Step-by-step explanation:

wariber [46]3 years ago
3 0

Answer:

x

= ln ( 3 ) 7 ln ( 3 )  + ln ( 7  )

Step-by-step explanation:

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The graph below shows a system of equations: The x coordinate of the solution to the equation is _______. (5 points)
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If f(x) = 2x ^ 2 - 5 and g(x) = x ^ 2 - 4x - 8 find (f - g)(x)
choli [55]

Answer:  (f-g)(x) is equivalent to f(x) - g(x)

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5 0
2 years ago
Construct a​ 99% confidence interval for the population​ mean, mu. Assume the population has a normal distribution. A group of 1
Zarrin [17]

Answer:

99% confidence interval for the population​ mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population​ mean is given by;

         P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean age of selected students = 22.4 years

             s = sample standard deviation = 3.8 years

             n = sample of students = 19

             \mu = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.878 < t_1_8 < 2.878) = 0.99  {As the critical value of t at 18 degree of

                                                freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.878) = 0.99

P( -2.878 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 2.878 \times {\frac{s}{\sqrt{n} } } ) = 0.99

P( \bar X -2.878 \times {\frac{s}{\sqrt{n} } < \mu < \bar X +2.878 \times {\frac{s}{\sqrt{n} } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X -2.878 \times {\frac{s}{\sqrt{n} } , \bar X +2.878 \times {\frac{s}{\sqrt{n} } ]

                                                 = [ 22.4 -2.878 \times {\frac{3.8}{\sqrt{19} } , 22.4 +2.878 \times {\frac{3.8}{\sqrt{19} } ]

                                                 = [19.891 , 24.909]

Therefore, 99% confidence interval for the population​ mean is [19.891 , 24.909].

6 0
3 years ago
Can you help me with these problems please?5-3/8
son4ous [18]
CAN  SOMEONE PLEASE HELP  ME ANSWER THIS  QUESTION 


7 0
3 years ago
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