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3 years ago

Two lines intersect in more than one point always sometimes never

1 answer:

5 0

The answer is never, that is, on a 2 dimensional plane. You can perform an experiment to see why it is the case. On curved surfaces though, two lines can intersect one another more than once. For instance, on the surface of planet Earth, two lines can intersect one another, both at the Earth's North Pole and South Pole.

You might be interested in

What percent of 40 is 28.4?

zalisa [80]

71% of 40 is 28.4

Divide 28.4 by 40:
$\frac{28.4}{40} = 0.71$

Change the decimal to a percentage by multiplying by 100:
$0.71 \times 100 = 71$

6 0

4 years ago

Read 2 more answers

-4(9n + 9) = -12(4n - 6).

WITCHER [35]

Answer:

n = 9

Step-by-step explanation:

Step 1: Write equation

-4(9n + 9) = -12(4n - 6)

Step 2: Solve for n

Distribute: -36n - 36 = -48n + 72

Add 48n to both sides: 12n - 36 = 72

Add 36 to both sides: 12n = 108

Divide both sides by 12: n = 9

Step 3: Check

Plug in n to verify if it's a solution.

-4(9(9) + 9) = -12(4(9) - 6)

-4(81 + 9) = -12(36 - 6)

-4(90) = -12(30)

-360 = -360

7 0

3 years ago

There are 4 green marbles and 2 red marbles in the jar. You just randomly draw one by one without replacement and stop when you

zalisa [80]

Answer:

Then the probability distribution is:

P(0) = 1/3

P(1) = 4/15

P(2) = 1/5

P(3) = 2/15

P(4) = 1/15

The expected value for X is:

EV = 1.33...

Step-by-step explanation:

We have a total of 6 marbles in the jar.

The probability of getting a red marble in the first try (X = 0) is equal to the quotient between the number of red marbles and the total number of marbles, this is:

P(0) = 2/6 = 1/3

The probability of drawing one green marble (X = 1)

is:

First, you draw a green marble with a probability of 4/6

Then you draw the red one, but now there are 5 marbles in the jar (2 red ones and 3 green ones), then the probability is 2/5

The joint probability is:

P(1) = (4/6)*(2/5) = (2/3)*(2/5) = 4/15

The probability of drawing two green marbles (X = 2)

Again, first we draw a green marble with a probability of 4/6

Now we draw again a green marble, now there are 3 green marbles and 5 total marbles in the jar, so this time the probability is 3/5

Now we draw the red marble (there are 2 red marbles and 4 total marbles in the jar), with a probability of 2/4

The joint probability is:

P(2) = (4/6)*(3/5)*(2/4) = (2/6)*(3/5) = 1/5

The probability of drawing 3 green marbles (X = 3)

At this point you may already understand the pattern:

First, we draw a green marble with a probability 4/6

second, we draw a green marble with a probability 3/5

third, we draw a green marble with a probability 2/4

finally, we draw a red marble with a probability 2/3

The joint probability is:

P(3) = (4/6)*(3/5)*(2/4)*(2/3) = (2/6)*(3/5)*(2/3) = (1/5)*(2/3) = (2/15)

Finally, the probability of drawing four green marbles (X = 4) is given by:

First, we draw a green marble with a probability 4/6

second, we draw a green marble with a probability 3/5

third, we draw a green marble with a probability 2/4

fourth, we draw a green marble with a probability 1/3

Finally, we draw a red marble with a probability 2/2 = 1

The joint probability is:

P(4) = (4/6)*(3/5)*(2/4)*(1/3)*1 = (1/5)*(1/3) = 1/15

Then the probability distribution is:

P(0) = 1/3

P(1) = 4/15

P(2) = 1/5

P(3) = 2/15

P(4) = 1/15

The expected value will be:

EV = 0*P(0) + 1*P(1) + 2*P(2) + 3*P(3) + 4*P(4)

EV = 1*(4/15) + 2*( 1/5) + 3*( 2/15) + 4*(1/15 ) = 1.33

So we can expect to draw 1.33 green marbles in this experiment.

5 0

3 years ago

what is the equation for the line that is perpendicular to the x-axis and passes through the point (4, -7)?

Sidana [21]

Step-by-step explanation:

perpendicular means to cross at a right angle (90 degrees).

so, any line perpendicular to the x-axis is parallel to the y-axis.

and any line parallel to the y-axis has only a defining x value. all points on that line have the same x value (while any value for y from -infinity to +infinity is valid).

the y-axis itself is

x = 0

the specified point here has an x value of 4.

so, the line we are looking for is

x = 4

to point out : this is NOT a function, because for the same x value we get more than 1 valid y values.

7 0

3 years ago

B(14, 12) A(-5,-2) A. Find the midpoint of Segment AB

IRISSAK [1]

The midpoint formula is (x1+x2/2, y1+y2/2
so you would do (-5+14)/2=4.5. (-2+12)/2=5
(4.5, 5)

3 0

3 years ago