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vazorg [7]
3 years ago
8

Please someone help me with this

Mathematics
2 answers:
shtirl [24]3 years ago
7 0

Answer:

2,-1.5

Step-by-step explanation:

To find the midpoint of a line segment, take the average of the x coordinates and y coordinates of the two points that make it up.

\frac{2+2}{2} ,\frac{4+(-7)}{2}

=\frac{4}{2} , \frac{-3}{2}\frac{4}{2} , \frac{-3}{2}

=2,-1.5

Zigmanuir [339]3 years ago
6 0

Here's the answer for you

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2x2 − 4x = 0<br> A. <br> 0, -4<br> B. <br> 0, -2<br> C. <br> 0, 2<br> D. <br> 2, 4
leonid [27]

Answer:

C

Step-by-step explanation:

We see that we can factor out 2x from the equation! So our equation becomes 2x(x-2) = 0.

Since the only way for things to multiply to equal to zero is if at least one of the numbers is 0.

So if x-2 is the 0, then x = 2.

If 2x is the 0, then x = 0.

So our answer is C. 0,2

5 0
3 years ago
LOOK AT PIC FOR PROBLEM‼️
Mademuasel [1]

Answer:

25 degrees

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
the walls of a square room need pain each of the four walls is 12 ft wide by 8.5 feet tall. One gallon of paint covers 75ft^2. h
Bingel [31]

Answer:

You would need 2 1/2 gallons of paint to finish the room.

Step-by-step explanation:

Step 1: 12 x 8.5

Step 2: you should get 102. Then multiply 102 x 4

Step 3: then divide by 150 (which is the quotent of 75 x 2)

Your finally should be 2.72 :)

8 0
3 years ago
Which of the following expressions correctly uses the properties of summations to represent
madam [21]

Answer:

Option C is correct.

7 \cdot \sum_{i=1}^{18} i^2 + 9 \cdot 18

Step-by-step explanation:

Given the expression:  \sum_{i=1}^{18} (7i^2+9)

Using properties of summation:

  • \sum_{i=1}^{n} (a+bi) =\sum_{i=1}^{n} a + \sum_{i=1}^{n} bi
  • \sum_{i=1}^{n} a = an

Using properties of summation in the given expression we have;

\sum_{i=1}^{18} (7i^2+9)

= \sum_{i=1}^{18} 7i^2 + \sum_{i=1}^{18} 9

=7 \cdot \sum_{i=1}^{18} i^2 + 9 \cdot 18

Therefore, the following given expression uses the properties of summation to represents is, 7 \cdot \sum_{i=1}^{18} i^2 + 9 \cdot 18


8 0
3 years ago
Read 2 more answers
Sample spaces For each of the following, list the sample space and tell whether you think the events are equally likely:
Schach [20]

Answer and explanation:

To find : List the sample space and tell whether you think the events are equally likely ?

Solution :

a) Toss 2 coins; record the order of heads and tails.

Let H is getting head and t is getting tail.

When two coins are tossed the sample space is {HH,HT,TH,TT}.

Total number of outcome = 4

As the outcome HT is different from TH. Each outcome is unique.

Events are equally likely since their probabilities \frac{1}{4} are same.

b) A family has 3 children; record the number of boys.

Let B denote boy and G denote girl.

If there are 3 children then the sample space is

{GGG,GGB,GBG,BGG,BBG,GBB,BGB,BBB}

The possible number of boys are 0,1,2 and 3.

Number of boys      Favorable outcome    Probability

           0                      GGG                        \frac{1}{8}

           1                    GGB,GBG,BGG          \frac{3}{8}

           2                   GBB,BGB,BBG           \frac{3}{8}

           3                       BBB                         \frac{1}{8}

Since the probabilities are not equal the events are not equally likely.

c)  Flip a coin until you get a head or 3 consecutive tails; record each flip.

Getting a head in a trial is dependent on the previous toss.

Similarly getting 3 consecutive tails also dependent on previous toss.

Hence, the probabilities cannot be equal and events cannot be equally likely.

d) Roll two dice; record the larger number

The sample space of rolling two dice is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we form a table that the number of time each number occurs as maximum number then we find probability,

Highest number        Number of times         Probability

           1                                   1                     \frac{1}{36}

           2                                  3                    \frac{3}{36}

           3                                  5                    \frac{5}{36}

           4                                  7                    \frac{7}{36}

           5                                  9                    \frac{9}{36}

           6                                  11                    \frac{11}{36}

Since the probabilities are not the same the events are not equally likely.

4 0
3 years ago
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