Complementary angles add to 90o
the other angle = x
the first angle = 3x - 4
x + 3x - 4 = 90
4x - 4 = 90
4x = 94
x = 94/4
x = 23.5
the first angle = 3*23.5 - 4 = 66.5
Answer:
The distance is:
Step-by-step explanation:
We re-write the equation of the line in the format:
Notice we divided the fraction of y by 2/2, and the fraction of z by 3/3.
In that equation, the director vector of the line is built with the denominators of the equation of the line, thus:
Then the parametric equations of the line along that vector and passing through the point (-2, 3, -4) are:
We plug them into the equation of the plane to get the intersection of that line and the plane, since that intersection is the image on the plane of the point (-2, 3, -4) parallel to the given line:
Then we solve that equation for t, to get:
Then plugging that value of t into the parametric equations of the line we get the coordinates of the intersection:
Then to find the distance we just use the distance formula:
So we get:
For each tank just divide the number of L by the number of fish to get the volume or fish.
For tank A it is 40/5=8, for tank B it is 100/12=8.3, and for tank C it is 180/23=7.8.
If you number them least to greatest, it is (tank C, tank A, tank B)
I hope this helps you
8x.2x+8x
8x (2x+1)
<span>The answer is that
4 kg of pure tin and 28 kg of 4% tin alloy were used to produce the 16% alloy.
</span>
Let,
x
= kg of pure 100% tin
and y = kg of 4% tin
x
+ y = 32
x
= 32 -y
1.00 x + 0.04 y = 0.16 x 32
By
solving the above system of equations we find:
Now
put the value of x in the above equation;
1
x (32 - y) + 0.04 y = 5.12
32
– y + 0.04y = 5.12
y – 0.04y = 32 – 5.12
0.96y
= 26.88
y = 26.88/0.96
y = 28 kg of 4% tin
Now
put the value of y in x = 32 – y
x = 32 – 28
<span>x = 4 kg of pure 100% tin</span>