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OLEGan [10]
3 years ago
7

Linda bought 13 plants to arrange along the border of her garden. How many distinct arrangements can she make if the plants are

comprised of 3 tulips, 6 roses, and 4 daisies?
I don't fully understand so I'd appreciate any help given! Thanks so much!
Mathematics
1 answer:
Ivahew [28]3 years ago
3 0

Answer:

its 13 mark me as brainlist pls:)

Step-by-step explanation:

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EH is a diameter of D. The measure of ef is (10x+ 8) and the measure of gh is (11x). Determine the values
jolli1 [7]

Answer:

x = 5

arcEF = 58degrees

arcGH = 55degrees

Step-by-step explanation:

Find the diagram attached

The sum of angle on the straight line EH is 180degrees

Hence arcEF+ arcFG + arcGH = 180

10x+8 + 67 + 11x = 180

21x + 75 = 180

21x = 180 - 75

21x = 105

x = 105/21

x = 5

Since EF = 10x+8

arcEF = 10(5) + 8

arcEF = 50+8

arcEF = 58degrees

Also, arcGH = 11x

arcGH = 11(5)

arcGH = 55degrees

8 0
3 years ago
You are choosing between two long-distance fun plans plan a has a monthly fee of $15 with a charge of 0.09 Per minute of long di
dusya [7]

Answer:

Step-by-step explanation:

This is a system of inequalities problem.  We first need to determine the expression for each phone plan.

Plan A charges $15 whether you use any minutes of long distance or not; if you use long distance you're paying $.09 per minute.  The expression for that plan is

.09x + 15

Plan B charges $12 whether you use any minutes of long distance or not; if you use long distance you're paying $.15 per minute.  The expression for that plan is

.15x + 12

We are asked to determine how many minutes of long distance calls in a month, x, that make plan A the better deal (meaning costs less).  If we want plan A to cost less than plan B, the inequality looks like this:

.09x + 15 < .15x + 12 and "solve" for x:

3 < .06x so

50 < x or x > 50

For plan A to be the better plan, you need to talk at least 50 minutes long distance per month.  Any number of minutes less than 50 makes plan B the cheaper one.

8 0
3 years ago
How to find the rule for the nth term of a geometric sequence with changing common ratio?
ki77a [65]
Hmmm... a geometric sequence MUST have a fixed common ratio. If it is changing, then the sequence you are looking at might not be a geometric sequence at all. We'd need to see an example to be sure.
6 0
3 years ago
Michelle's father deposited $1,000 into a savings account when she was born. The annual interest rate is
Zarrin [17]

Answer:

0. $1,000  1. $1,045  2. $1,092.03  3. $1,141.17  4. $1,192.52. 5. $1,246.18     6. $1,302.26  7. $1,360.86  8. $1,422.10

Step-by-step explanation:

First you start with the beginning balance of $1,000 dollars, then you multiply that by 1.045 to get $1,045 dollars after one year. Then you multiply $1,045 by 1.045 to get $1,092.025 (monetarily correct, it would be $1,092.03) after the second year. Then you multiply $1,092.025 (keeping it un-rounded for precision) by 1.045 to get $1,141.16612 after the third year. Then you multiply $1141.16612 by 1.045 to get $1,192.5186 after the fourth year. Multiply $1,192.5186 by 1.045 to get $1,246.18193 after the fifth year. Multiply $1,246.18193 by 1.045 to get $1,302.26012 after the sixth year. Multiply $1,302.26012 by 1.045 to get $1,360.86182 after the seventh year. Multiply $1,360.86182 by 1.045 to get $1,422.10061 after the eighth year. Basically, Michelle is going to be a trust fund baby by the time she's twenty and she won't have to worry about college if she works hard and does well in high school.

8 0
3 years ago
HELP ME PLEASEEEE SOMEONEEE
patriot [66]
Probably 48 but i dont know
4 0
3 years ago
Read 2 more answers
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