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liubo4ka [24]
3 years ago
7

There are 5 exams in a semester. You have scored 77, 90, 85, and 100 on the previous four exams. What must you make on the fifth

exam to get an average of exactly 86 for the marking period?
Mathematics
1 answer:
siniylev [52]3 years ago
5 0

Answer:

<h2>The correct answer for this question is 78.</h2>

Step-by-step explanation:

  • The average or mean of any variable or mathematical phenomenon is calculated as the division of the sum of all the numbers or items within the particular variable by the total number of items or numbers within the variable.
  • In this case, the marks of the 4 exams in the semester are 77,90,85 and 100 respectively.There are total 5 exams in the semester.
  • Let's suppose that the marks for the 5th exam is x.
  • Therefore, based on the mathematical formula to compute average or mean,to get an overall average of 86 including all the 5 exams, one has to get:-

   \frac{77+90+85+100+x}{5}=86

  77+90+85+100+x=430

  x=430-77-90-85-100

  x=78

  • Hence, based on the above calculations,one has has to get 78 on the 5th exam to obtain an overall average of exactly 86.

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Answer:

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Step-by-step explanation:

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3 years ago
Check my answer (I chose B)
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Each CD at a music store is sold for $10. If n represents the number of CDs sold, which equation could be used to find the total
Art [367]

Answer:

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Step-by-step explanation:

We know that

Each CD is sold for 10 dollars

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Hope this helps!

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2 years ago
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Alex17521 [72]
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3 years ago
F(n)=5.(-2)n-1<br>Complete the recursive formula of f(n).​
Alex73 [517]

Answer:

a(n) = (-2)(a_{n-1})

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Step-by-step explanation:

The given expression is in the form of the explicit formula of a geometric sequence.

f(n) = a(r)^{n-1}

Where 'a' = First term of the sequence

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Recursive formula of a geometric sequence is,

a(n) = (a_{n-1}).(r)^{n-1}

a(n) = (-2)(a_{n-1})

Where, a_{1}=5

So the recursive formula will be a(n) = (-2)(a_{n-1})

6 0
3 years ago
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