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devlian [24]
3 years ago
12

Elements are arranged in groups by similar atomic structure on the periodic table. This allows for an element's properties to be

predicted based on general periodic trends. One of these trends, electron affinity, increases up a group and to the right along a period and can be defined as the ______________.
A) energy required to add an electron
Eliminate
B) energy required to emit an electron
C) energy required to excite an electron
D) energy required to remove an electron
Chemistry
1 answer:
arlik [135]3 years ago
3 0

Answer:

A) energy required to add an electron

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The concentration of potassium cyanide (KCN) in a sample of water is 9.65 x 10-7 M. Assume the density of
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The concentration in ppm is 0.06 ppm

<h3>How to convert to PPM?</h3>

There are several unit of concentration in chemistry. Let us recall that concentration is the amount of substance that is present in a solution. Thus we have;

Concentration = 9.65 x 10-7 M

Molar mass of potassium cyanide = 65 g/mol

Thus;

M = ppm/MM * 1000

M = molar concentration

MM = molar mass

M * MM * 1000 = ppm

ppm = 9.65 x 10-7 M * 65 g/mol * 1000

ppm = 0.06 ppm

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2 years ago
Which state of matter contains atoms that are completely ionized?
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This is actually known as the fourth state of matter which is the<em> plasma</em>. The plasma is basically a hot ionized gas. It consists of equal number of protons and electrons. This can be obtained by subjecting a gas to a high energy, for example, a laser beam. The energy from the laser beam causes a rapid energy increase of the atoms, such that they become ionized.
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Which of the following statements is true?
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D) during chemical reactions the number and types of atoms
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What is the compound KNC called?
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The answer is <span>Potassium cyanide</span>
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g The decomposition reaction of A to B is a first-order reaction with a half-life of 2.42×103 seconds: A → 2B If the initial con
Tanzania [10]

Answer:

In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.

Explanation:

The equation used to calculate the constant for first order kinetics:

t_{1/2}=\frac{0.693}{k}} .....(1)

Rate law expression for first order kinetics is given by the equation:

t=\frac{2.303}{k}\log\frac{[A_o]}{[A]} ......(2)

where,  

k = rate constant

t_{1/2} =Half life of the reaction = 2.42\times 10^3 s

t = time taken for decay process = ?

[A_o] = initial amount of the reactant = 0.163 M

[A] = amount left after time t =  66.8% of [A_o]

[A]=\frac{66.8}{100}\times 0.163 M=0.108884 M

k=\frac{0.693}{2.42\times 10^3 s}

t=\frac{2.303}{\frac{0.693}{2.42\times 10^3 s}}\log\frac{0.163 M}{0.108884 M}

t = 1,409.19 s

1 minute = 60 sec

t=\frac{1,409.19 }{60} min=23.49 min

In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.

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3 years ago
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