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3 years ago

Write the expression using a positive exponent. (-9)-4

Mathematics

2 answers:

Alex73 [517]3 years ago

8 0

-9+-4 for example like this question

thanx

saveliy_v [14]3 years ago

5 0

(-9)^-4 as a positive exponent = (-1/9^4). If I misread the question please advise and I’ll correct answer. Thank you

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Help please last one

Monica [59]

Y=1/2x+8

Step by step explanation This is how I got the answer to your question and I gave you the solution I hope this helps you out

8 0

2 years ago

What is 5/6 + 3/8 in the simplest form

zlopas [31]

5/6 + 3/8

Convert to denominators of 24:

20/24 + 9/24

Add the numerators:

29/24

Convert to mixed number:

1 5/24

3 0

3 years ago

Read 2 more answers

Please please help me out

Inessa [10]

Answer:

26.6 m

Step-by-step explanation:

Given the figures are similar

linear ratio = a : b

area ratio = a² : b²

here

area ratio = 16 : 25, then

linear ratio = 4 : 5 ( square root of both area ratio parts )

let the perimeter of the larger figure be x, then by proportion

$\frac{4}{21.3}$ = $\frac{5}{x}$ ( cross- multiply )

4x = 106.5 ( divide both sides by 4 )

x ≈ 26.6

Hence perimeter of larger figure is approximately 26.6 m

3 0

3 years ago

A quadratic polynomial with real coefficients and leading coefficient is called if the equation is satisfied by exactly three re

lukranit [14]

p(1) = 1

Let p(x) = x2 + bx = c

then, p(p(x)) = (x2 + bx + c)² + b(x2 + bx + c) + c

Sum of roots of p(p(x)) is given by = - (coefficient of x3/constant term)

= -2b/c2+bc+c = f(a,b) (say)

For critical points,

∂f/∂c = 0 and ∂f/∂b = 0

= 2b(2c+b+1)/c2+bc+c = 0 and - {( c2+bc+c)²- 2b (c)/ ( c2+bc+c)²}= 0

= b(2c+b+1) =0

= b= 0 or b= - (1+2c) = -(2c(c+1))/c2+bc+c = 0

If c=0 , b= -1 => c= 0 or c=-1

If c = -1 ,b = 1

thus we have the following possibility for (b,c)

(0,0) , (0,-1) , (-1,0) ,(1,-1).

At (0,0) f(0,0) = not defined

(0,-1) f(0,-1) = 0

(1,-1) f(1,-1) = 2

(-1,0) is not possible.

p(x) = (x2 +x-1)² + (x2 +x-1) -1

= p(1) = (1+1-1)² + (1+1-1) -1

= 1

Hence, p(1) = 1

Learn more about the sum of roots here brainly.com/question/10235172

#SPJ4

8 0

1 year ago

Given: measure 1, measure 2, measure 3, and measure 4 formed by two intersecting segments Prove: measure 1 and measure 3 are con

lesantik [10]

Step-by-step explanation:

The text below that are formatted in bold and underlined font are the solutions to the missing boxes in your given problem.

<h3><u>Explanation:</u></h3>

Given that ∠1, ∠2, ∠3, and ∠4 are formed by two intersecting segments, and that:

∠1 and ∠2 form a linear pair

∠2 and ∠3 form a linear pair

These linear pair relationships suggest that by the Linear Pair Postulate:

<u>∠1 and ∠2 are supplementary</u>. ⇒ Linear Pair Postulate

<u>∠2 and ∠3 are supplementary</u>. ⇒ Linear Pair Postulate

m∠2 + m∠ 3 = 180° ⇒ <u>Definition of supplementary angles</u>.

<u>m∠1 + m∠3 = m∠2 + m∠ 3</u> ⇒ Substitution Property of Equality.

m∠1 = m∠3 ⇒ <u>Subtraction Property of Equality</u>.

4 0

2 years ago