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3 years ago

Write the expression using a positive exponent. (-9)-4

Mathematics

2 answers:

Alex73 [517]3 years ago

8 0

-9+-4 for example like this question

thanx

saveliy_v [14]3 years ago

5 0

(-9)^-4 as a positive exponent = (-1/9^4). If I misread the question please advise and I’ll correct answer. Thank you

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The population of a certain city can be modeled by P = 130,000(1.018)t.

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Answer:

D.the population change is inconsistent

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1 year ago

During a camping trip, Tony hikes 13 1/2 mi in one day. He hikes 2 1/4 mi each hour. How many hours does it take Tony to complet

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2 years ago

Read 2 more answers

9. The approximate circumferences of Earth

Molodets [167]

Answer and explanation:

1) Given : Circumference of Earth $C_E= 365,882\ km$

Circumference of Saturn $C_S= 4.01\times 10^4\ km$

To find : How many times greater is the circumference of Saturn than the circumference of Earth?

Solution :

Let x be the number of times greater is the circumference of Saturn than the circumference of Earth.

According to question,

$x=\frac{C_E}{C_S}$

$x=\frac{365882}{4.01\times 10^4}$

$x=\frac{365882}{40100}$

$x=9.124$

Therefore, 9.124 times greater is the circumference of Saturn than the circumference of Earth.

2) Number 0.037854921

Estimate to the nearest hundredth.

The hundredth number is 3 and thousandth number is 7.

As thousandth number 7 is greater than 5.

So, hundredth number is added by 1 and rest became zero.

i.e. $0.037854921\approx 0.04$

3) Compare the numbers $6 \times 10{-6}$ and $2\times 10{-8}$

$6 \times 10{-6}=\frac{6}{1000000}$

$2\times 10{-8}=\frac{2}{100000000}=\frac{0.02}{1000000}$

As the denominator is same compare the numerator,

0.02<6 or 6>0.02

So, $6 \times 10{-6}>2\times 10{-8}$

Therefore, $6 \times 10{-6}$ is greater than $2\times 10{-8}$

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2 years ago

Find the equation of the line shown.

Annette [7]

Answer:

4x + 5 = y

i think y= 5

Step-by-step explanation:

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2 years ago

The line l is tangent to the circle with equation x² + y2 = 169 at the point P.

timofeeve [1]

Given:

The equation of a circle is

$x^2+y^2=169$

A tangent line l to the circle touches the circle at point P(12,5).

To find:

The gradient of the line l.

Solution:

Slope formula: If a line passes through two points, then the slope of the line is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Endpoints of the radius are O(0,0) and P(12,5). So, the slope of radius is

$m_1=\dfrac{5-0}{12-0}$

$m_1=\dfrac{5}{12}$

We know that, the radius of a circle is always perpendicular to the tangent at the point of tangency.

Product of slopes of two perpendicular lines is always -1.

Let the slope of tangent line l is m. Then, the product of slopes of line l and radius is -1.

$m\times m_1=-1$

$m\times \dfrac{5}{12}=-1$

$m=-\dfrac{12}{5}$

Therefore, the gradient or slope of the tangent line l is $-\dfrac{12}{5}$ .

6 0

2 years ago