Answer: s > 5
Step-by-step explanation:
-s² + 25s - 100 > 0
Coefficient of s² is -1, multiply the equation through by -1.
-1 × (-s² + 25s - 100)
s² — 25s + 100
ax² + bx + c
Then you get the factors x and y that gives x + y = b and xy = c
b = -25 and c = 100, x = -20 and y = -5
-20 × -5 = 100 and -20 + -5 = -25
Then
s² — 20s — 5s + 100 > 0
Factorising,
s (s — 20) — 5(s — 20) > 0
(s — 5)(s — 20) > 0
(s — 5) > 0 and (s — 20) > 0
s>5 and s>20
s > 5
Hope this Helps?
Only the first one works
y = 3(-1)-2 = -5
y = -(0) -6 = -6 not -2
This is a substitution problem...
Answer:
No.
Step-by-step explanation:
No because if we substitute the given values into the equation they do not fit:
y = 7x
x = 1 and y = 4:
Left side = 4
right side = 7*1 = 7.
Using x to represent our missing values and the fact that there are two missing values gives us x + x = 2x. Because it's the sum of these numbers and 0.34, we get the equation 2x + 0.34; now we set it equal to 2, 2x + 0.34 = 2.
To solve, 1st subtract 0.34 on both sides to get 2x = 1.66. Now divide by 2 on both sides to get x = 0.83.
So your decimals are 0.34, 0.83, and 0.83
Answer: (-1/-24)(2-2/72)
(-0.04)(2-0.02)
(-0.04)(2.02)
-0.0808
Step-by-step explanation:
