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erma4kov [3.2K]
3 years ago
13

How many phone numbers are possible for one area code if the first four numbers are 202-1 , in that order , and the last three n

umbers are 1-7-8 in any order
Mathematics
1 answer:
Mkey [24]3 years ago
3 0

6 phone numbers are possible for one area code if the first four numbers are 202-1

<u>Solution:</u>

Given that, the first four numbers are 202-1, in that order, and the last three numbers are 1-7-8 in any order  

We have to find how many phone numbers are possible for one area code.

The number of way “n” objects can be arranged is given as n!

Then, we have three places which changes, so we can change these 3 places in 3! ways

n! = n \times (n - 1)!

Hence 3! is found as follows:

3! = 3 \times (3-1)!\\\\3! = 3 \times 2!\\\\3! = 3 \times 2 \times 1 = 6

So, we have 6 phone numbers possible for one area code.

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Explain why 4×3/5 equals 12 /5. draw a picture
BigorU [14]
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3 years ago
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erik [133]

Answer:

2490

Step-by-step explanation:

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2 years ago
Beth is taking out a loan to purchase a new home. She is financing $50,000 for 25 years at an interest rate of 14.25%. What is h
kozerog [31]
The present value (PV) of a loan for n years at r% compounded t times a year where there is equal P periodic payments is given by:

PV=P\left( \frac{1-\left(1+ \frac{r}{t} \left)^{-nt}}{ \frac{r}{t} } \right)

Given that <span>Beth is taking out a loan of PV = $50,000 to purchase a new home for n = 25 years at an interest rate of r = 14.25%. Since she is making the payment monthly, t = 12.

Her monthly payment is given by:

50,000=P\left( \frac{1-\left(1+ \frac{0.1425}{12} \right)^{-25\times12}}{ \frac{0.1425}{12} } \right) \\  \\ =P\left( \frac{1-(1+0.011875)^{-300}}{ 0.011875 } \right)=P\left( \frac{1-(1.011875)^{-300}}{ 0.011875 } \right) \\  \\ =P\left( \frac{1-0.028969}{ 0.011875 } \right)=P\left( \frac{0.971031}{ 0.011875 } \right)=81.770994P \\  \\  \therefore P= \frac{50,000}{81.770994} =\$611.46

Therefore, her monthly payment is about $611.50
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3 years ago
ABCD is a rectangle. Angle D = 3x + 20 + 7x - 3x. Solve for x
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