The exterior angles of triangle UVW are ∠X, ∠Y, and ∠Z, and they are adjacent to ∠U, ∠V, and ∠W, respectively.
1 answer:
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The complete question in the attached figure
we have that
m∠1=<span>58°
</span>m∠7=?
we know that
m∠1+m∠3=180°------------> supplementary angles
and
m∠3=m∠7--------------------> corresponding angles
then
m∠3=180°-m∠1-----------> m∠3=180°-58°=122°
m∠7=m∠3=122°
the answer is m∠7=122°
we have that
m∠1=<span>58°
</span>m∠7=?
we know that
m∠1+m∠3=180°------------> supplementary angles
and
m∠3=m∠7--------------------> corresponding angles
then
m∠3=180°-m∠1-----------> m∠3=180°-58°=122°
m∠7=m∠3=122°
the answer is m∠7=122°
1.
In any trapezoid, the length of the midsegment is
substituting the known values:
2.
Notice that since D and have the same y-coordinate, then DE is horizontal, and since F and D have the same x-coordinate, FD is vertical.
Thus FD and DE are perpendicular, so the triangle FED is a right triangle.
The median drawn from the right angle, is equal to half the hypotenuse.
That is, |DO|=1/2 |FE|, thus |OE|=|OF|=|OD|, are all radii of the circle centered at O.
O is the midpoint of EF, and is found by the Midpoint formula:
Answer:
1. 14
2. (4, 3)
In any trapezoid, the length of the midsegment is
substituting the known values:
2.
Notice that since D and have the same y-coordinate, then DE is horizontal, and since F and D have the same x-coordinate, FD is vertical.
Thus FD and DE are perpendicular, so the triangle FED is a right triangle.
The median drawn from the right angle, is equal to half the hypotenuse.
That is, |DO|=1/2 |FE|, thus |OE|=|OF|=|OD|, are all radii of the circle centered at O.
O is the midpoint of EF, and is found by the Midpoint formula:
Answer:
1. 14
2. (4, 3)