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Firlakuza [10]
4 years ago
12

Find x in d equation below 2x-3=7 ​

Mathematics
1 answer:
yan [13]4 years ago
5 0

Answer:

5

Step-by-step explanation:

2x-3=7

   +3   +3

2x=10

/2   /2

x=5

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An object is launched vertically in the air at 36.75 meters per second from a 6-meter-tall platform. Using the projectile motion
nasty-shy [4]
I HAVE THE SAME QUESTION
5 0
3 years ago
The graph of y = f(x) is shown below. Determine the value of x when f(x) = -4? ? y 10 9 8 7 6 5 ur 4 3 NO C 2 1 X -10 -9 -8 -7 -
Brilliant_brown [7]

Answer:

A

Step-by-step explanation:

the function f(x) is a straight line. The "-4" means that the graph moves down 4 units. Point A is at y=-4, so this is the point. You can graph the equation and you'll see that it hits point A.

4 0
3 years ago
A basketball player attempts 15 baskets in a game, He makes 9 of the attempted basket. which ratio describe the number of basket
Taya2010 [7]

Answer:

3:5

Step-by-step explanation:

We are looking for the ratio of baskets made to baskets attempted

made: attempted

9:15

We can divide each number by 3

9/3: 15/3

3:5

The ratio of baskets made: attempted  is 3:5

3 0
3 years ago
Solve the inequality
Nady [450]

Answer:

x >= -6

Step-by-step explanation:

Multiply:

(1/3)x + 1 >= (1/2)x + 1/2 - (-1/4)x

Combine like terms:

(1/3)x + 1 >= (1/4)x + 1/2

Move the x's on one side and the integers on another:

(1/3)x - (1/4)x >= 1/2 - 1

(1/12)x >= -1/2

x >= -6

I hope this helped! :D

5 0
3 years ago
Perpendicular to the line y =6 - 3x; passes through (-3, -1)
madam [21]

Answer:

y=\frac{1}{3}x

Step-by-step explanation:

<u>Perpendicular lines</u>

Perpendicular lines have slopes whose product is -1.  In other words, to find a line that is perpendicular to a given line, the new line must have a that is the opposite reciprocal of the original line.

<u>Passing through a point</u>
Additionally, if a line contains a point, then the point must be a solution to the equation (meaning, when you plug in the "x" and "y", the equation must be true).

<u>Finding our perpendicular line</u>

<u>Work on slope first</u>

To find the slope of the original line, rewrite the original line in slope-intercept form: y=mx+b

y=6-3x\\y=6+(-3x)\\y=(-3x)+6\\y=-3x+6\\y=-\frac{3}{1}x+6

In this form, the slope is the number multiplied to the "x", so the original slope is -3/1.

Thus, the slope of the new perpendicular line will be the opposite reciprocal of -3/1 ... which is 1/3.

Writing what we do know about the new perpendicular line, we have y=\frac{1}{3}x+b

<u>Making sure it passes through the point</u>
This new line is also supposed to contain the point (-3,-1), so (-3,-1) must be a solution to the equation, for whatever constant-value the "b" is.  To find out the "b", substitute the known quantities, and solve:

-1=\frac{1}{3} (-3)+b\\-1=-1+b\\(-1)+1=(-1+b)+1\\0=b

Substituting this into our equation:

y=\frac{1}{3}x+(0)\\y=\frac{1}{3}x

<u>Conclusion</u>

So, the equation for a line that is perpendicular to the original line y=6-3x, and that also passes through (-3,-1) is y=\frac{1}{3}x

6 0
2 years ago
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