Answer:
First option.
Third option.
Fourth option.
Step-by-step explanation:
For this exercise is important to remember that equivalent expression have the same value.
Then given the following expression provided in the exercise:
You can find equivalent expression by:
- Changing the position of 
:
(This matches with the first option)
- Solving the multiplication indicated. Then:
(This matches with the fourth option)
- Writting 
inside the parentheses:
(This matches with the third option)
Answer:
D. All of the above.
Step-by-step explanation: Please brainliest if correct!
Answer:
(2,6) and (-2,6) is in the second box
(8,-2) and (8,2) is in the first box
(-5,7) and (-5,-7) is in the first box
(-3,-3) and (3,-3) is in the second box
Answer:
s = height above ground
s = 60 + 20 t - 4.9 t^2 (standard physics equation on earth)
at t = 0
s = 60 (clearly :)
now when does it hit the bleak earth?
That is when s = 0
4.9 t^2 - 20 t -60 = 0
solve quadratic and use the positive t (the negative t was back before you threw it if you had thrown it from the ground)
t = 6.09 or - 2.01
use t = 6.09
now to do the last part there are two obvious ways to get t at the peak
1. look for vertex of parabola
2. look for halfway between t = -2.01 and t = 6.09
I will do it the hard (11) waay by completing the square
4.9 t^2 - 20 t = -(s-60)
t^2 - 4.08 t = -.204 s + 12.2
t^2 - 4.08 t +2.04^2 = -.204 s +12.2 + 4.16
(t-2.04)^2 = -.204(s-80.2)
so
top at 80.2 meters at t = 2.04 s
===============
quick check on time
should be average of 6.09 and -2.01
=4.08 /2 = 2.04 check
