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Lunna [17]
3 years ago
13

Write an inequality for the following statement. 4 is less than c

Mathematics
1 answer:
Fed [463]3 years ago
3 0

Answer:

= c - 4

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Will Identify the outlier in the data set. 77, 73, 78, 78, 71, 75, 120, 75, 77, 72, 75, 70 The outlier is​
o-na [289]

Answer:

120

Step-by-step explanation:

120

every other number is in the 70s

7 0
3 years ago
Plzlzzlzlzlzl help mememememe
sweet [91]

Answer:

1/2z=3/4

z=3/4 x 2

z=3/2

6 0
3 years ago
Which of the following is true of algorithms and heuristics for solving real-life problems?
professor190 [17]

Answer: Under the given option, the following is true of algorithms and heuristics for solving real-life problems: <u><em>Heuristics are shortcut strategies. </em></u>

Algorithms are known as step by step plan of action for resolving a issue. It leads to a specific solution, methodically.

whereas;

Heuristics are known as short‐cut, step‐saving reasoning scheme or generalization that bring forth a solution speedily but possibly with an error.

<u><em>Therefore, the correct option is (a)</em></u>

4 0
3 years ago
Using the distributive property to find the product (y – 4)(y2 + 4y + 16) results in a polynomial of the form y3 + 4y2 + ay – 4y
Crank

Answer:

The answer to your question is a = 16

Step-by-step explanation:

Polynomial

                  (y - 4) (y² + 4y + 16)

Process

1.- Multiply y by each term of the polynomial

                y(y² + 4y + 16) = y³ + 4y² + 16y

2.- Multiply -4 by each term of the polynomial

                -4(y² + 4y + 16) = -4y² - 16y - 64

3.- Write both results

                y³ + 4y² + 16y - 4y² - 16y - 64

In bold we notice that a = 16

8 0
3 years ago
Changing Bases to Evaluate Logarithms In Exercise, use the change-of-base formula and a calculator to evaluate the logarithm.
Ymorist [56]

Answer:

\frac{3}{2}

Step-by-step explanation:

Changing Bases to Evaluate Logarithms

log_{16}(64)

Apply change of base formula'

log_b(a)= \frac{log a}{log b}

log term should be the numerator and denominator is the log base

log_{16}(64)

log_{16}(a)= \frac{log 64}{log 16}

64 is 4^3  and 16 is 4^2

log_{16}(a)= \frac{log 4^3}{log 4^2}

Move the exponent before log

\frac{3log 4}{2log 4}

top and bottom has same log so cancel it out

\frac{3}{2}

3 0
3 years ago
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