Write an inequality for the following statement. 4 is less than c

A group of 59 randomly selected students have a mean score of 29.5 with a standard

algol [13]

Answer:

$29.5-1.671\frac{5.2}{\sqrt{59}}=28.37$

$29.5+1.671\frac{5.2}{\sqrt{59}}=30.63$

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

Step-by-step explanation:

Information given

$\bar X = 29.5$ represent the sample mean

$\mu$ population mean

s= 5.2 represent the sample standard deviation

n=59 represent the sample size

Confidence interval

The confidence interval for the true mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=59-1=58$

The Confidence interval is 0.90 or 90%, the significance is $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value is $t_{\alpha/2}=1.671$

Now we have everything in order to replace into formula (1):

$29.5-1.671\frac{5.2}{\sqrt{59}}=28.37$

$29.5+1.671\frac{5.2}{\sqrt{59}}=30.63$

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

8 0

3 years ago

Ms Thomas drove at a constant rate for 45. She drove 39 miles during that time. If distance is determined by the equation d=rt w

Cerrena [4.2K]

Answer:

Ms. Thomas was driving at constant rate of 52 miles/hour.

Step-by-step explanation:

Given:

Total time to travel (t) = 45 minutes

Distance drove (d) = 39 miles

we need to find the constant rate in miles per hour at which she was driving.

Solution:

Now we know that;

We need to find constant rate at miles per hour;

But time is given in minutes.

So we will convert minutes into hour by dividing by 60 we get;

time $t =\frac{45}{60}= 0.75\ hrs$

Now we know that;

Distance is equal to rate times time.

framing in equation form we get;

distance $d =rt$

Or

rate $r= \frac{d}{t} = \frac{39}{0.75}= 52 \ mi/hr$

Hence Ms. Thomas was driving at constant rate of 52 miles/hour.

6 0

3 years ago

Based on the measures provided in the diagram, determine the measure of AEG

MArishka [77]

Answer:

277°

Step-by-step explanation:

The measure of arc AEG = AB + BE + EF + FG

The central angle is congruent to the arc that subtends it

∠ ECB = 180° - 44° = 136° ( adjacent angles )

∠ECF = ∠ ACB = 44° ( vertical angles ), thus

AEG = 44° + 136° + 44° + 53° = 277°

8 0

4 years ago

Soit trois nombres consécutifs. Lorsque l’on soustrait le double du deuxième nombre du quadruple du

irina [24]

Answer:

Les trois nombres sont 5, 6 et 7.

Step-by-step explanation:

Soit x le premier nombre.

x + 1 sera le second et x + 2 sera le troisième.

On pose l'équation :

2x + 3(x + 1) = 4(x + 2)

2x + 3x + 3 = 4x + 8

5x - 4x = 8 - 3

x = 5

4 0

3 years ago

The product of 4 and a number f decreased by 2 is 15

Debora [2.8K]

Answer: The number is: "2 " .

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Step-by-step explanation:

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Write the expression; which is an equation, as follows:

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" 4x − 12 = 2(-x) " ; in which "x" represents "the number for which we shall solve" .

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Note:

If the "number" = "x" ; the "opposite of the number" = " -x " ;

___________________________________________

Rewrite as: " 4x − 12 = -2x " ;

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→ Add "12" ; & add "2x" ; to EACH SIDE of the equation:

4x − 12 + 12 + 2x = -2x + 12 + 2x ;

to get: 6x = 12 ;

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Now, divide each side of the equation by "6" ;

to isolate "x" on one side of the equation; & to solve for "x" ;

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6x / 6 = 12 / 6 ;

to get: x = 2 .

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Answer: The number is: "2 " .

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Let us check our answer, by plugging in "2" for "x" in our original equation:

_____________________________________________________

→ " 4x − 12 = 2(-x) " ;

Let us plug in "2" for "x" ; to see if the equation holds true; that is; if both side of the equation are equal; when "x = 2" ;

→ " 4(2) − 12 = ? 2(-2) ??

→ 8 − 12 = ? -4 ? ;

→ -4 = ? -4 ?? Yes!

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7 0

3 years ago

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