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Alina [70]
3 years ago
11

Come on y'all....plz

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
7 0
Yeah the guy above me is right
boyakko [2]3 years ago
6 0

Answer:

In image

Step-by-step explanation:

You need to draw it yourself

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Allison went to the store to buy some walnuts. The price per pound of the walnuts is
spin [16.1K]

Answer:

Step-by-step explanation:

4 0
3 years ago
Express this to single logarithm
zzz [600]

Answer:  \log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

  1. log(A) + log(B) = log(A*B)
  2. log(A) - log(B) = log(A/B)
  3. B*log(A) = log(A^B)

From there, we can then say the following:

\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}

8 0
2 years ago
(4a) to the third power divided by (b-2) ; a=2 and b=4
Bingel [31]
(4(2)=8*8*8=512÷6=85.333333
(4-2)=2
8-2=6
8*2=16
8÷2=4
8+2=10
whichever operation it is

7 0
3 years ago
Expand: f(x)= x^4- x^3+x^2+x-
emmainna [20.7K]
F(x) = x (x^3 - x^2 + x + 1)

6 0
3 years ago
If varies inversely as . It is known that = 10 when = 3, find the value of when = 5.
Leto [7]

Answer:

y = 6

Step-by-step explanation:

If x varies inversely proportional as y.

x=\dfrac{k}{y}, k is constant of proportionality

or

k = xy

When x = 3 and y = 10

k = 3×10

k = 30

Put x = 5,

y=\dfrac{k}{x}\\\\y=\dfrac{30}{5}\\\\y=6

So, the value of y is 6 when x is 5.

8 0
2 years ago
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