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antoniya [11.8K]
3 years ago
5

Which description is correct for the polynomial 4x² +3x +5?

Mathematics
2 answers:
jeka57 [31]3 years ago
7 0

the answer is cubic trinomial
Allisa [31]3 years ago
4 0

Answer: quadratic trinomial

Step-by-step explanation:

took the test

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Find the other endpoint of the line segment with the given endpoint and midpoint. Endpoint: (9,8) Midpoint (0,9)​
shepuryov [24]

Answer:

(-9, 10)

Step-by-step explanation:

The location of the midpoint of a line with endpoint at (x_1,y_1) and (x_2,y_2) is given as (x, y). The location of x and y are:

x = \frac{x_1+x_2}{2},y=\frac{y_1+y_2}{2}

Given the endpoint (9,8) and Midpoint (0,9), the location of the other endpoint can be gotten from:

0=\frac{9+x_2}{2}\\ \\9+x_2=0\\\\x_2=-9\\\\Also,9=\frac{8+y_2}{2}\\ \\8+y_2=18\\\\y_2=18-8\\\\y_2=10

Hence the endpoint is at (x2, y2) which is at (-9, 10)

5 0
3 years ago
What is the greatest common factor of 24 and 9
Katyanochek1 [597]

Answer:

The Greatest Common Factor of 24 and 9 is 3.

8 0
2 years ago
Read 2 more answers
What is the value of ?<br> 18 - (2 x ? ) = ? x 4
Dmitry_Shevchenko [17]

Answer:

?= 3

Step-by-step explanation:

let x = ?

18-2x=4x

6x=18x

x=3

6 0
3 years ago
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he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s
sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

P(X

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) =[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

NORMSDIST(6.366)-NORMSDIST(-1.47)

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

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2 years ago
Please see attached! Surface area
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Surface area is 10 cm
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