We have been given that a 208-yard-long road is divided into 16 parts of equal length.
Let us find length of each part.
Length of each part will be 13 yards.
We are told that Mr. Ward paints a 4-yard-long strip in each part.
Now we will subtract length of painted strip from length of each equal part to find length of unpainted strip of each part of the road.
Therefore, length of each unpainted strip will be 9 yards.
Answer:
12 in
Step-by-step explanation:
The area (A) of a trapezoid is calculated as
A = 
h(b₁ + b₂ )
where h is the height and b₁, b₂ the parallel bases
Given h = 6, b₁ = 8 and A = 60 , then
× 6 × (8 + b₂ ) = 60 , that is
3(8 + b₂ ) = 60 ( divide both sides by 3 )
8 + b₂ = 20 ( subtract 8 from both sides )
b₂ = 12
The length of the second base is 12 inches
First find out how much the 4 volleyball nets are by using 4*28 which would equal to 112. Now subtract 112 from 250 and that leaves you with 138. Then you divide 138 by 7 which will give you about 19.7 which you need to take all decimals out since it isn’t an whole number. The gym teacher can only buy 19 volleyballs.
Answer:
The answer is C.
Step-by-step explanation:
Answer:
1 3/7 quarts should be drained off and replaced with pure antifreeze.
1 3/7 ≈ 1.4286
Current amount of antifreeze in quarts is -
30/ 100 × 10 = 3
40% ---> 4 quarts
Let the amount drained of and replaced with antifreeze be x-
The amount left after draining off is 10 − x.
The amount of antifreeze is 30/ 100 (10−x).
30/100(10-x)+x=4
3-3/10x+x=4
3+x(1-3/10)=4
x=1*10/7=1 3/7 quarts
check;
10- 1 3/7 = 8 4/7
=(30/100*8 4/7)+1 3/7
=(3/10 * 60/7) + 10/7
=3*6/7 + 10/7
=28/7
=4
4 liters of pure antifreeze is mixed into 10 quarts.
