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3 years ago

Rainer bought 1.43 pounds of lunch meat at the store for $10.98. What was the unit rate (price) of the lunch meat?

Mathematics

1 answer:

adoni [48]3 years ago

4 0

<span>the lunch meat would beeeeeeeeee would be $7.68
</span>

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Solve the system, or show that it has no solution. (If there is no solution, enter NO SOLUTION. If there are an infinite number

liberstina [14]

Answer:

The system has an infinite set of solutions $(x,y) = (x, \frac{x-5}{4})$

Step-by-step explanation:

From the first equation:

$20x - 80y = 100$

$20x = 100 + 80y$

$x = \frac{100 + 80y}{20}$

$x = 5 + 4y$

Replacing on the second equation:

$-14x + 56y = -70$

$-14(5 + 4y) + 56y = -70$

$-70 - 56y + 56y = -70$

$0 = 0$

This means that the system has an infinite number of solutions, considering:

$x = 5 + 4y$

$4y = x - 5$

$y = \frac{x - 5}{4}$

The system has an infinite set of solutions $(x,y) = (x, \frac{x-5}{4})$

8 0

3 years ago

A grocery store paid $85 for 4 crates of milk. How much was one crate of milk?

Ivan

Answer:

21.25

Step-by-step explanation:

85÷4=21.25

7 0

3 years ago

What expression is equivalent to the expression 5 + 3y + 5y?

nlexa [21]

Answer:

5 + 8y

Step-by-step explanation:

hope this helps, pls mark brainliest :D

8 0

3 years ago

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What is the answer too this,it’s rational numbers - 3.3(6)= ?

Sloan [31]

Answer:

the answer is -19.8.

5 0

4 years ago

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10) Thirty-seven percent of the American population has blood type O+. What is the probability that at least four of the next fi

lisabon 2012 [21]

Answer:

0.06597

Step-by-step explanation:

Given that thirty-seven percent of the American population has blood type O+

Five Americans are tested for blood group.

Assuming these five Americans are not related, we can say that each person is independent of the other to have O+ blood group.

Also probability of any one having this blood group = p = 0.37

So X no of Americans out of five who were having this blood group is binomial with p =0.37 and n =5

Required probability

=The probability that at least four of the next five Americans tested will have blood type O+

= $P(X\geq 4)\\= P(X=4)+P(x=5)\\= 5C4 (0.37)^4 (1-0.37) + 5C5 (0.37)^5\\= 0.06597$

7 0

3 years ago

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